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PIT_PIT [208]
2 years ago
8

What is the density of krypton gas (MM = 83.8 g/mol) at 3.00 atm and 100. °C? g/L

Chemistry
1 answer:
ycow [4]2 years ago
4 0

Answer:

8.22 g/dm³

Explanation:

Applying,

PV = nRT............... Equation 1

Where P = pressure of krypton, V = Volume of krypton, n = number of moles, R = molar gas constant, T = Temperature

But,

number of mole (n) = mass(m)/molar mass(m')

n = m/m'.............. Equation 2

Substitute equation 2 into equation 1

PV = mRT/m'

P = (m/V)(RT)/m'................ Equation 3

Also,

Density (D) = Mass(m)/Volume(V)

D = m/V.............. Equation 4

Substitute equation 4 into equation 3

P = DRT/m'

D = Pm'/RT.................... Equation 5

From the question,

Given: P = 3.00 atm, T = 100°C = (273+100) = 373 K, m' = 83.8 g/mol

Constant: R = 0.082atm.dm³.K⁻¹.mol⁻¹

Substitute these values into equation 5

D = (3×83.8)/(0.082×373)

D = 251.4/30.586

D = 8.22 g/dm³

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Answer:

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Explanation:

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In this case, since such substance has the same amount of protons and electrons we can infer it is an atom whose number of neutrons is defined by considering its atomic mass or mass number and atomic number which is actually equal to the number of protons and electrons (36):

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