Answer:
8.22 g/dm³
Explanation:
Applying,
PV = nRT............... Equation 1
Where P = pressure of krypton, V = Volume of krypton, n = number of moles, R = molar gas constant, T = Temperature
But,
number of mole (n) = mass(m)/molar mass(m')
n = m/m'.............. Equation 2
Substitute equation 2 into equation 1
PV = mRT/m'
P = (m/V)(RT)/m'................ Equation 3
Also,
Density (D) = Mass(m)/Volume(V)
D = m/V.............. Equation 4
Substitute equation 4 into equation 3
P = DRT/m'
D = Pm'/RT.................... Equation 5
From the question,
Given: P = 3.00 atm, T = 100°C = (273+100) = 373 K, m' = 83.8 g/mol
Constant: R = 0.082atm.dm³.K⁻¹.mol⁻¹
Substitute these values into equation 5
D = (3×83.8)/(0.082×373)
D = 251.4/30.586
D = 8.22 g/dm³
