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PIT_PIT [208]
2 years ago
8

What is the density of krypton gas (MM = 83.8 g/mol) at 3.00 atm and 100. °C? g/L

Chemistry
1 answer:
ycow [4]2 years ago
4 0

Answer:

8.22 g/dm³

Explanation:

Applying,

PV = nRT............... Equation 1

Where P = pressure of krypton, V = Volume of krypton, n = number of moles, R = molar gas constant, T = Temperature

But,

number of mole (n) = mass(m)/molar mass(m')

n = m/m'.............. Equation 2

Substitute equation 2 into equation 1

PV = mRT/m'

P = (m/V)(RT)/m'................ Equation 3

Also,

Density (D) = Mass(m)/Volume(V)

D = m/V.............. Equation 4

Substitute equation 4 into equation 3

P = DRT/m'

D = Pm'/RT.................... Equation 5

From the question,

Given: P = 3.00 atm, T = 100°C = (273+100) = 373 K, m' = 83.8 g/mol

Constant: R = 0.082atm.dm³.K⁻¹.mol⁻¹

Substitute these values into equation 5

D = (3×83.8)/(0.082×373)

D = 251.4/30.586

D = 8.22 g/dm³

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www.ausetute.com.au/intermof.html


7 0
3 years ago
If you burn 55.6 g of hydrogen and produce 497 g of water, how much oxygen reacted?
tester [92]

Answer:

441.28 g Oxygen

Explanation:

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2H₂(g) + O₂(g) → 2H₂O(l)

Mass of hydrogen = 55.6 g

Number of moles of hydrogen

Moles = Mass/Molar mass

          = 55.6 g ÷ 2.016 g/mol

          = 27.8 moles

The mole ratio of Hydrogen to Oxygen is 2:1

Therefore;

Number of moles of oxygen = 27.5794 moles ÷ 2

                                               = 13.790 moles

Mass of oxygen gas will therefore be;

Mass = Number of moles × Molar mass

Molar mass of oxygen gas is 32 g/mol

Mass = 13.790 moles × 32 g/mol

<h3>          = 441.28 g</h3><h3>Alternatively:</h3>

Mass of hydrogen + mass of oxygen = Mass of water

Therefore;

Mass of oxygen = Mass of water - mass of hydrogen

                          = 497 g - 55.6 g

<h3>                           = 441.4 g </h3>
6 0
3 years ago
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What is the name of group 5a
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Answer:

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Explanation:

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3 years ago
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Answer:

General equation for a double-displacement reaction:  

AB + CD --> AC + BD

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Copper (II) chloride forms a blue colored solution.

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• sodium chloride – NaCl silver nitrate – AgNO₃  

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The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

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Explanation:

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