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earnstyle [38]
3 years ago
15

Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm2.Ho

w many rectangles could alex draw with an area of 11cm2
?
Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

Number of rectangles  could alex draw with an area of 11cm² = 1

Step-by-step explanation:

Minimum length in centimeter grid = 1 cm

Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm²

That is

                     12 = 1 x 12

                     12 = 2 x 6

                     12 = 3 x 4

          These are the 3 different rectangles with an area of 12cm².

Now we need to find how many rectangles could alex draw with an area of 11cm².

                     11 = 1 x 11

So only one factorization is possible.

Number of rectangles  could alex draw with an area of 11cm² = 1

stiks02 [169]3 years ago
3 0

Answer:

2.75 or 2

Step-by-step explanation:


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Three ways to find the slope of a line: You may have two points #(x_1,y_1)# and #(x_2,y_2)# (often one or both of these points may be intercepts of the #x# and/or #y# axes). The slope is given by the equation. #m=(y_2-y_1)/(x_2-x_1)#. You may have a linear equation that is either in the form or can be manipulated into the form. #y = mx + b#.

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Paul [167]

Answer:

0.6395 ; 0.9657 ; 0.7333

Step-by-step explanation:

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(b) longer than 5 minutes

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Z = −1.821428

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(c) between 8 and 15 minutes

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3 years ago
Compare the perimeters of the two regular figures. Which statement is true?
adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

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=\frac{(6-2){\timeS}180^{\circ}}{6}

=\frac{(4){\timeS}180^{\circ}}{6}

=120^{\circ}

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

\frac{MP}{MQ}=cos60^{\circ}

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Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be=\frac{(n-2){\timeS}180^{\circ}}{8}

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Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

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julsineya [31]
Yes you are correct
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