Six hundred ninty three thousand, five thousand six hundred ninty nine
Three hundred fourty thousand two thousand and eighty nine
I’m confused on the comma for the last 2?
Answer:
(-21, 16)
Step-by-step explanation:
A is at (-33, 0) and B is at (0, 44),
A point that divides the line segment in a ratio of 4:7 also divides the differences of the x-and y-coordinates in the same ratio.
If we divide each distance into 11 equal parts and choose a length 4/11 of the distance, the other part will be 7/11 of the distance. The two parts will be in a ratio of 4:7.
For the x-coordinate,
x₂ - x₁ = 0 - (-33) = 0 + 33 = 33
(4/11) × 33 = 12
-33 + 12 = -21
The x-coordinate of M is (-21, 0).
For the y-coordinate,
y₂ - y₁ = 44 - 0 = 44
(4/11) × 44 = 16
0 + 16 = 16
The y-coordinate of M is (0, 16).
The coordinates of M are then (-21, 16).
The diagram below shows the point M that divides AB in a 4/7 ratio.
Answer:
y = x + 40
Step-by-step explanation:
I'm assuming to simplify this.
Use the distribution property first.
y = -4x - 8 · 4x + 32
Combine like terms.
y = x · 8 + 32
Solve.
y = x + 40
Hope this this helps!
Answer:
Incomplete question
Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.
a. Determine the pre-collision momentum of the ball.
b. Determine the post-collision momentum of the ball.
c. Determine the momentum change of the ball.
Answer:
A. 1.5353kgm/s
B. 1.6963kgm/s
C. 0.161kgm/s
Step-by-step explanation:
A. The pre-collision momentum of the ball = mass of ball × velocity of ball
Mass of ball = 57.5g = 0.0575kg
Velocity of ball = 26.7m/s
Pre-collision momentum of ball = 0.0575×26.7
= 1.5353kgm/s
B. Post collision momentum of the ball = mass of ball × velocity of ball after impact
Velocity of ball after impact = 29.5m/s
Post collision momentum of ball after impact = 0.0575×29.5
= 1.6963kgm/s
C. Momentum change of ball = momentum after impact - momentum before imlact
= 1.6963kgm/s - 1.5353kgm/s
= 0.161kgm/s
Answer:
orange
Step-by-step explanation:
hope it help
