Ask question

Ask question

All categories

2 years ago

14

1 square root x times 4 square root x

1 answer:

Reil [10]2 years ago

8 0

Answer:

4√x

Step-by-step explanation:

4√x

You might be interested in

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

2 years ago

Which of the following statements is true ? HELLLLP ASSSSAPP TRYAN GRADUATE UKKK

Soloha48 [4]

Answer:

Both are irrational

Step-by-step explanation:

$\sqrt{\frac{4}{9} }$ is a trick as it does simplify to $\frac{2}{3}$ , but that is irrational

4 0

2 years ago

Given that IK is a midsegment of AFGH, find GH.

guajiro [1.7K]

It’s either C or B but I’m not sure

8 0

3 years ago

Read 2 more answers

QUESTION Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm.

STALIN [3.7K]

4.3 bc it’s right and i did the assignment

5 0

2 years ago

How do I do this? 50 points, please answer

xz_007 [3.2K]

Check the picture below.

now, the midsegment of a triangle, besides being half the base, we have to bear in mind that is a "mid" segment, is a segment that lies half-way along the segments it touches.

so for the triangle above, well, the midsegment DE is cutting the segment BC it two equal halves, BE and EC, that means that $\stackrel{x}{BE}~~ = ~~\stackrel{8}{EC}$ .

5 0

1 year ago