PART 1

A karate studio charges $35 for the first course and $22. 50 for each course after that, even if the student leaves the course e

VashaNatasha [74]

The Cena can take 7 courses

We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.

<h3>What is the condition we can write here?</h3>

$22.50x + 35 = 170$

for solving this linear equation

First, subtract 35 from both sides.

$22.50x = 135$

isolate x so divide both sides by 22.50.

$x=\frac{135}{22.50}$

Therefore we get x = 6

Remember to add the additional class, so x is actually 7.

So,the Cena can take 7 courses.

To learn more about the linear equation visit:

brainly.com/question/1549055

3 0

2 years ago

SOMEONE PLEASE HELP!

prisoha [69]

Answer:

$XY=16.2$

Step-by-step explanation:

It is given that the two figures are similar. This means that the ratio between the corresponding sides is equal. In essence, a side in the larger figure over its corresponding side in the smaller figure is equal to another side in the larger figure over its corresponding side in the smaller figure. Therefore, one can set up a proportion and solve to find the unknown side.

$\frac{WX}{ST}=\frac{XY}{TU}$

Substitute,

$\frac{18}{3}=\frac{XY}{2.7}$

Simplify,

$6=\frac{XY}{2.7}$

Inverse operations,

$6=\frac{XY}{2.7}$

$6(2.7)=XY\\\\16.2=XY$

8 0

3 years ago

REPEATED REASONING What happens to the circumference and the area of a circle when you double the radius? triple the radius?

GalinKa [24]

Answer: So when you double the radius, the area goes up by 4 times because 2 squared is 4. The area will always go up by the square of how much the radius goes up. By contrast, the circumference will only double -- from 12.56 to 25.12 because you do not square the radius (or diameter) -- you just multiply it by pi.

5 0

2 years ago

Find the area of a square with side length 13 ft

Strike441 [17]

The area of a square is the length of the side squared. 13^2 = 169
The area of a square with a side length of 13 feet is 169 feet.

Hope this helps =)

8 0

3 years ago

What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$

5 0

3 years ago

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