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Anton [14]
4 years ago
9

It is possible to have a circular cross section in a right rectangular prism

Mathematics
1 answer:
TiliK225 [7]4 years ago
7 0
Pretty sure that you can't. It contains right angles
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Which statements describe one of the transformations performed on f(x) =x^2 to create g(x)=2x^2+5?
Serjik [45]

Answer:

do u know the answer ik it's five units up but that it

7 0
3 years ago
Which is the equation of the parabola with focus (6, 2) and vertex (6, –4)?
SVETLANKA909090 [29]

Based on the calculations, the equation of this parabola is equal to (x - 6)² = 16(y + 4).

<h3>How to determine the equation of this parabola?</h3>

Mathematically, the standard equation with the vertex for a parabola is given by:

(y - k)² = 4a(x - h) for horizontal parabola.

(x - h)² = 4a(y - k) for vertical parabola.

<u>where:</u>

  • h and k are the vertex.
  • a is a point.

By critically observing the points, we can deduce that both the focus and vertex lie on the same vertical line x = 6.

<u>Given the following data:</u>

Focus with points = (6, 2).

Vertex (h, k) = (6, –4).

<u>Note:</u> a = 2 - (-4) = 2 + 4 = 6.

Substituting the given parameters into the formula, we have;

(x - 6)² = 4 × 4(y - (-4))

(x - 6)² = 16(y + 4).

Read more on parabola here: brainly.com/question/2346582

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8 0
2 years ago
Solve the absolute value equation 23 – 4 = 10. Use comma to separate the solutions, no spaces.
hichkok12 [17]

Answer: ?????

Step-by-step explanation: Is it doable? 23 - 4 = 19

8 0
3 years ago
The two pictures are the questions and question five is what i need help with.
Mama L [17]

Answer:yes they do

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
For a sample size of 115 and a population parameter of 0.1,what is the standard deviation of the normal curve that can be used t
Helga [31]

Answer:

A) 0.028

Step-by-step explanation:

Given:

Sample size, n = 115

Population parameter, p = 0.1

The X-Bin(n=155, p=0.1)

Required:

Find the standard deviation of the normal curve that can be used to approximate the binomial probability histogram.

To find the standard deviation, use the formula below:

\sigma = \sqrt{\frac{p(1-p)}{n}}

Substitute figures in the equation:

\sigma = \sqrt{\frac{0.1(1 - 0.1)}{115}}

\sigma = \sqrt{\frac{0.1 * 0.9}{115}}

\sigma = \sqrt{\frac{0.09}{115}}

\sigma = \sqrt{7.826*10^-^4}

\sigma = 0.028

The Standard deviation of the normal curve that can be used to approximate the binomial probability histogram is 0.028

5 0
3 years ago
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