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iragen [17]
3 years ago
5

Solve the quadratic formula 2x^2+9x=-7

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

Step-by-step explanation:

2x² + 9x = -7

2x² + 9x + 7 = 0

When we multiply we should get 2*7 = 14 and when we add we should get 9. Find the factors of 14 ---> 1,2,7,14. Factors are 2,7 as when we multiply we get 14 and we we add, get 9

2x² + 2x + 7x + 7 = 0

2x( x + 1) + 7 (x + 1) = 0

(x  + 1)(2x + 7) = 0

                   

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Help please need those answers
icang [17]

We know: The sum of the measures of the angles of a triangle is equal 180°.

We have: m∠A =65°, m∠B =  (3x - 10)° and m∠C = (2x)°.

The equation:

65 + (3x - 10) + 2x = 180

(3x + 2x) + (65 - 10) = 180

5x + 55 = 180        <em>subtract 55 from both sides</em>

5x = 125          <em>divide both sides by 5</em>

x = 25

m∠B =  (3x - 10)° → m∠B =  (3 · 25 - 10)° = (75 - 10)° = 65°

m∠C = (2x)° → m∠C = (2 · 25)° = 50°

<h3>Answer: x = 25, m∠B = 65°, m∠C = 50°</h3>
8 0
3 years ago
What is the answer to this 4×3^2?<br><br>Evaluate the expression. ​
Neporo4naja [7]
The answer to this question is 36
6 0
2 years ago
Read 2 more answers
13 plus 5 times a number is no more than 30
omeli [17]
From what I'm reading from this question, there's one answer.

13 + 5 * 1 = 18 

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5 0
3 years ago
Perpendicular lines are always, sometimes , never coplanar
daser333 [38]

They are always on a coplanar

8 0
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Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Lubov Fominskaja [6]

Answer:

  yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

__

For the first parabola, the point of intersection is ...

  y^2 = 4(-y-1)

  y^2 +4y +4 = 0

  (y+2)^2 = 0

  y = -2 . . . . . . . . one solution only

  x = -(-2)-1 = 1

The point of intersection is (1, -2).

__

For the second parabola, the equation is the same, but with x and y interchanged:

  x^2 = 4(-x-1)

  (x +2)^2 = 0

  x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0
3 years ago
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