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MA_775_DIABLO [31]
3 years ago
8

A pendulum bob is given some initial potential energy by raising it. Next it is released.

Physics
2 answers:
Lisa [10]3 years ago
8 0
This is a slightly tricky one, but I believe the best answer is C.

The central concept to this question in physics is the "conservation of energy". Energy is always conserved, it is never lost, it simply is converted into other forms.

Initially the pendulum is at rest with potential energy due to gravity and height. When it is released, this potential energy is converted into kinetic energy as it accelerates. However it is true that as the pendulum moves through the air, this will produce an aerodynamic resistance and generate heat, slowing the pendulum down slightly. So the total potential energy at the beginning would be equal to the sum of the kinetic energy at maximum velocity (the lowest part of the swing) + losses due to friction. If this experiment occurred in a vacuum there would be no aerodynamic losses.
Mumz [18]3 years ago
4 0
B, It is equal to the kinetic energy at the bottom of the swing I think. 
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2 years ago
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snow_tiger [21]

the work W done on the charge in terms of q, V, and/or I. is W =qV.

question was incomplete, the complete question is -  

Part A Focus on a single charge, q, passing through the resistor. Find the work W done on the charge by the electric field in the resistor. Express the work W done on the charge in terms of q, V, and/or I.

<h3>What is Work?</h3>

Transferring energy into an item to cause some displacement is what is referred to as work. The ability to perform tasks is referred to as energy. The work is consistently the same. Kinetic and potential energy are two examples of the various forms of energy.

Work done to move the charge across the potential difference is given as

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so work done is given as

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2 years ago
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Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: Vf^{2} = Vo^{2} - 2gh and h=Vo*t - \frac{g*t^{2} }{2}, First we need to find the height to time iqual to 3.04 s using the formula: h=Vo*t - \frac{g*t^{2} }{2} and remember that golf ball was released from the rest (Vo= 0 (m/s)) so h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}, we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using Vf^{2} = Vo^{2} - 2gh solving for Vf, we get: Vf = \sqrt{Vo^{2}-2*g*h } replacing the values given Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }, so we get: Vf = 29.79 (m/s).

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