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3 years ago

What is the overall charge of the wall?

Physics

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

The overall charge on the wall is zero.

Explanation:

Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.

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Answers please!! i have to give it up in 2 hours!!

aleksklad [387]

Answer:

this isn't physics this is german

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3 years ago

The masses of two heavenly bodies are 2×10‘16’ and 4×10 ‘22’ kg respectively and the distance between than is 30000km. find the

ycow [4]

$F = 5.93×10^{13}\:\text{N}$

Explanation:

Given:

$m_1= 2×10^{16}\:\text{kg}$

$m_2= 4×10^{22}\:\text{kg}$

$r = 30000\:\text{km} = 3×10^7\:\text{m}$

Using Newton's universal law of gravitation, we can write

$F = G\dfrac{m_1m_2}{r^2}$

$\:\:\:\:=(6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2)\dfrac{(2×10^{16}\:\text{kg})(4×10^{22}\:\text{kg})}{(3×10^7\:\text{m})^2}$

$\:\:\:\:= 5.93×10^{13}\:\text{N}$

3 0

3 years ago

This equation represents Newton's Second Law of Motion, F=ma. It shows the relationship of force, mass, and acceleration. How wi

inn [45]

A. The acceleration will be doubled

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3 years ago

When a spinning star shrinks in radius, it speeds up. Which of the following statements explains this phenomenon?

Sever21 [200]

Answer:

B.)Angular momentum is always conserved

Explanation:

Angular momentum is given by:

$L=mvr$

where

m is the mass of the object

v is its speed

r is the distance between the object and the centre of its circular trajectory

In absence of external torques, angular momentum is always conserved. That means that for the spinning star, if its radius r decreases (because it shrinks), in order for L (the angular momentum) to be conserved, the speed (v) must increases, therefore the spinning star speeds up.

So, the correct choice is

B.)Angular momentum is always conserved

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3 years ago

The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o

Damm [24]

Answer : The value of equilibrium constant $K_c$ for the following reaction will be, 2.4

Explanation : Given,

Initial concentration of $N_2O_4$ = 0.45 M

Equilibrium concentration of $NO_2$ = 0.30 M

$K_c$ is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of $NO_2$ at equilibrium = $2\times 0.30M=0.6M$