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iogann1982 [59]
3 years ago
6

Please help! 100 points + 50 + brainlist!!!

Physics
2 answers:
ANTONII [103]3 years ago
8 0

Answer: the answer to thatis 6289.

because i did the math on a caculator

Explanation:

irakobra [83]3 years ago
4 0

Explanation:

First find the displacement in the x direction:

dₓ = 449 cos 66° + 1112 cos 169° + 1571 cos 26°

dₓ = 182.6 − 1091.6 + 1412

dₓ = 503 km

Next, find the displacement in the y direction:

dᵧ = 449 sin 66° + 1112 sin 169° + 1571 sin 26°

dᵧ = 410.2 + 212.2 + 688.7

dᵧ = 1311 km

The magnitude is:

d² = dₓ² + dᵧ²

d² = (503)² + (1311)²

d = 1404 km

The angle is:

tan θ = dᵧ / dₓ

tan θ = 1311 / 503

tan θ = 2.61

θ = 69°

1404 km and 69° north of east from New Orleans is approximately Toledo.

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A passenger on a Ferris wheel moves in a vertical circle at a constant speed. Are the forces on her balanced?
vovikov84 [41]

C.  The force is a constant change,  because her position on the Ferris wheel will constantly change.  I believe this is the answer, but use sources to double check.  I might use different vocab. then your teachers.  

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A soccer player takes a corner kick, lofting a stationary ball 30.0° above the horizon at 18.0 m/s. If the soccer ball has a mas
Radda [10]

Answer:

change in momentum, \Delta p=7.65 \,kg.m.s^{-1}

  • \Delta p_x= 6.6251 \,kg.m.s^{-1}
  • \Delta p_y= 3.825 \,kg.m.s^{-1}

Average Force, F=144.3396\,N

  • F_x=125.0018\,N
  • F_y=72.1698\,N

Explanation:

Given:

angle of kicking from the horizon, \theta= 30^{\circ}

velocity of the ball after being kicked, v=18 m.s^{-1}

mass of the ball, m=0.425\, kg

time of application of force, t=5.3\times 10^{-2}\,s

We know, since body is starting from the rest

\Delta p=m.v.....................(1)

\Delta p=0.425\times 18

\Delta p=7.65 \,kg.m.s^{-1}

Now the components:

\Delta p_x= 7.65\times cos 30^{\circ}

\Delta p_x= 6.6251 \,kg.m.s^{-1}

similarly

\Delta p_y= 7.65\times sin 30^{\circ}

\Delta p_y= 3.825 \,kg.m.s^{-1}

also, impulse

I=F\times t.........................(2)

where F is the force applied for t time.

Then from eq. (1) & (2)

F\times t=m.v

F\times 5.3\times 10^{-2}= 7.65

F=144.3396\,N

Now, the components

F_x=144.3396\times cos 30^{\circ}

F_x=125.0018\,N

&

F_y=144.3396\times sin 30^{\circ}

F_y=72.1698\,N

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A sound wave travels in air toward the surface of a freshwater lake and enters into the water. The frequency of the sound does n
Shkiper50 [21]

Answer:

Explanation:

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velocity of sound in water at 20⁰C is 1481 m /s

The wavelength of the sound is 2.86 m in the air so its frequency

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This frequency of  119.93 will remain unchanged in water .

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What is the average speed of a kangaroo that hops 60 m in 5 s ?
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The formula for average speed is
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