3 years ago

An engine converts 95% of its energy to mechanical. What happens to the other 5% of its energy?

Physics

1 answer:

Elza [17]3 years ago

6 0

Answer:

Here, 5% of energy wasted as a heat lost or work done against frictional forces.

Explanation:

No engine has yet made that can convert its all input energy into mechanical energy. Some of the input energy goes in vain in the form of heat and friction.

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What are the different types of Energy transformations and Energy Transfers?

Harman [31]

Explanation:

Here are some of the ways that energy can change (transform) from one type to another:

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

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3 years ago

Choose the correct association for: dense bushes<br><br> savanna<br> rain forest or jungle

Gemiola [76]

Answer:

Climate is determined by averaging the seasonal weather conditions for a region over a period of many ______ years

Choose the correct association for: dense bushes rain forest or jungle

Choose the correct association for: plains savanna

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2 years ago

During electrical storms, a bolt of lightning can transfer 10 C of charge in 2.0 µs (the amount of time can vary considerably).

nydimaria [60]

Answer:

Explanation:

charge, q = 10 C

time, t = 2 micro second

Current, i = q / t

i = 10 / (2 x 10^-6) = 5 x 10^6 A

(a)

distance, d = 1 m

the formula for the magnetic field is given by

$B = \frac{\mu_{0}}{4\pi}\frac{2i}{d}$

$B = 10^{-7}\frac{2\times 5\times 10^{6}}{1}$

B = 1 Tesla

Now the distance is d' = 1 km = 1000 m

$B' = \frac{\mu_{0}}{4\pi}\frac{2i}{d}$

$B' = 10^{-7}\frac{2\times 5\times 10^{6}}{1000}$

B' = 0.001 Tesla

(b) The magnetic field of earth is Bo = 3 x 10^-5 tesla

B / Bo = 3.3 x 10^4

B'/Bo = 33.3

4 0

3 years ago

On the Moon's surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distanc

dimulka [17.4K]

Answer:

4.88 x 10∧-8 sec

Explanation:

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3 years ago

An observer on the earth sees a spaceship approaching at 0.54c. The ship then launches an exploration vehicle that, according to

AURORKA [14]

Answer:

Explanation:

Expression for relative velocity

= $\frac{v_1+v_2}{1+\frac{v_1v_2}{c^2} }$

= (.54 + .82 )c/ $1+ \frac{.54 \times.82}{1}$

= 1.36 c / 1.4428

= .94 c

β = .94

6 0

3 years ago