Answer:
are corresponding angles and are congruent to each other.
are alternate exterior angles and thus congruent to each other.
are interior angles on the same side, and they are supplementary(sum=180°).
Step-by-step explanation:
Given:
Line 
Line
is traversal.
By angle properties we can name the angle relationship of given angle pairs.
are corresponding angles and are congruent to each other.
are alternate exterior angles and thus congruent to each other.
are interior angles on the same side, and thus they are supplementary.
Answer:
350 miles
Step-by-step explanation:
Let x represent the miles driven
The cost with the first plan will be represented by 0.40x + 70
The second plan will be represented by 0.60x
Set these 2 expressions equal to each other and solve for x:
0.40x + 70 = 0.60x
70 = 0.20x
350 = x
So, Susan will have to drive 350 miles for the cost to be the same
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Answer:
C) Both
Step-by-step explanation:
The given equation is:

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.
Using this property:

So, Erik's solution strategy would work.
Now, let us discuss about Caleb's solution strategy:
Multiply
i.e.
= 
So, the equation becomes:

Comparing this equation to standard quadratic equation:

a = 3, b = -10, c = -8
So, this can be solved using the quadratic formula.


The answer is same from both the approaches.
So, the correct answer is:
C) Both