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2 years ago

A 3

Mathematics

1 answer:

Andrew [12]2 years ago

7 0

Answer:

There are (63) combinations. The notation means "six choose three". Out of six items (flavors) choose three.

(nk)=n!k!(n−k)!.

(63)=6!3!3!.

Think of it this way. There are 6 ways to choose a flavor. Once you choose, there are 5 ways to choose the next. After that, there are 4 flavors left. which is 6!/3!=6⋅5⋅4⋅3⋅2⋅13⋅2⋅1=6⋅5⋅4=120.

But, you could have chosen {chocolate,vanilla,strawberry} and you get the same combination as {vanilla, strawberry, chocolate} so we have to divide by 3!=3⋅2⋅1=6 to account for the order of choosing.

So the number of combinations of flavors is (63)=1206=20.

<h3>Mark me a brainlist</h3>

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A probability is the number of desired outcomes divided by the number of total outcomes.

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Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

$P(B) = \frac{10}{91}$

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3 years ago

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3 years ago

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Olin [163]

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<u>Explanation:</u>

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a = √3

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ΔBAC ≅ ΔBQR

Therefore,

$\frac{BQ}{BA} = \frac{QR}{AC}$

$\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}$

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

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In ΔAPQ,

(AP)² + (QP)² = (AQ)²

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Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

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a² + 3 = 4a²

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