The system of linear equations that relates x and y:
x= 15 + y
5 x = 2 y+ 525
We will solve this system using substitution method:
5(15 + y)=2 y + 525
75 + 5 y = 2 y + 525
5 y - 2 y = 525 - 75
3 y = 450, y = 450 : 3 y = 150
x = 15 + y x = 15 + 150 x = 165
Answer: Aaron´s height is 165 cm and Peter´s height is 150 cm.
Hold on just have to type before I can see the question
Answer:
0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability that a sophomore non-Chemistry major
Out of 92 students, 9 are non-chemistry major sophomores. So

Then a junior non-Chemistry major are chosen at random.
Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
1. Change the fraction to a decimal 0.625
2.Line up the decimals
incorrect correct
-0.615 -0.615
0.625 0.62
0.62 0.625
(C) 6 + 3√3
<u>Explanation:</u>
Area of the square = 3
a X a = 3
a² = 3
a = √3
Therefore, QR, RS, SP, PQ = √3
ΔBAC ≅ ΔBQR
Therefore,


In ΔBAC, BA = AC = BC because the triangle is equilateral
So,
BQ = √3
So, BQ, QR, BR = √3 (equilateral triangle)
Let AP and SC be a
So, AQ and RC will be 2a
In ΔAPQ,
(AP)² + (QP)² = (AQ)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
Similarly, in ΔRSC
(SC)² + (RS)² = (RC)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
So, AP and SC = 1
and AQ and RC = 2 X 1 = 2
Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR
Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3
Perimeter = 6 + 3√3
Therefore, the perimeter of the triangle is 6 + 3√3