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DaniilM [7]
3 years ago
9

Covert 1.3902 to centiliters​

Mathematics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

`13.902

Step-by-step explanation:

Tju [1.3M]3 years ago
5 0
13,902 is your answer for this question
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You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which
stellarik [79]
To model this situation, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
where
A is the final amount after t years 
P is the initial deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

For account A: 
We know for our problem that P=2000 and r= \frac{2.25}{100} =0.0225. Since the interest is compounded monthly, it is compounded 12 times per year; therefore, n=12. Lets replace those values in our formula:
A=2000(1+ \frac{0.0225}{12} )^{12t}

For account B:
P=2000, r= \frac{3}{100} =0.03, n=12. Lest replace those values in our formula:
A=2000(1+ \frac{0.03}{12} )^{12t}

Since we want to find the time, t, <span>when  the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span>2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000

Now that we have our equation, we just need to solve for t:
2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000
(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}
(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}&#10;{2}
ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})
12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})
t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})
t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}
17.47

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>
5 0
3 years ago
Is the graph of 6x2 - 2y = 7 a line? Explain.
Hoochie [10]

Answer:

No, it is a parabola. (assuming that you meant to write 6x² - 2y = 7).

Step-by-step explanation:

If there is a square in the x or y, this gives it away that it cannot be a straight line.

6 0
4 years ago
What can you say about the sum of consecutive odd numbers starting with 1? that is, evaluate 1, 1c3, 1c3c5, 1c3c5c7, and so on,
Mice21 [21]

Let us add consecutive odd numbers and try to find any relationship.

1. 1

2. 1+3 = 4 ( square of 2 i.e 2^{2} )

3. 1+3+5 = 9 ( 3^{2} )

4.  1+3+5+7 =  16 (4^{2} )

5. 1+3+5+7+9 = 25 (5^{2} )

6. 1+3+5+7+9+11 = 36 ( 6^{2} )

7. 1+3+5+7+9+11+13 = 49 (7^{2} )

If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to 7^{2}. The sum of the numbers in the fifth line is equal to 5^{2}.

4 0
3 years ago
Pls help many thanks
salantis [7]

So, let's make these two values improper fractions so they're easier to work with. 4+\frac{1}{3}=\frac{12}{3}+\frac{1}{3}=\frac{13}{3} 3+\frac{1}{2}=\frac{6}{2}+\frac{1}{2}=\frac{7}{2}

So, to get the rate he grew in those months we have:

\frac{\frac{13}{3} \text{inches}}{\frac{7}{2}\text{months}} =\frac{26\text{inches}}{21\text{months}}

And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:

\frac{\frac{26}{21} \text{inches}}{\text{month}}\approx \frac{1.24\text{inches}}{\text{month}} aka he grew 1.24 inches in a month.

7 0
3 years ago
Read 2 more answers
If x2 - 6x - 16, what are the x-intercepts?​
romanna [79]
If that’s meant to be x^2 - 6x - 16
Then factorise to (x+2)(x-8)
So x intercepts are -2 and 8
8 0
3 years ago
Read 2 more answers
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