Answer:
a)
And if we convert this interval into % we got (47.615%, 58.385%)
b) For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than most students at PCC own a car
Step-by-step explanation:
We can begin calculating the best estimator for the true proportion of students at PCC who own a car:

Part a
The confidence level is 95% , and the significance level would be given by
and
. And the critical values would be given by:
The confidence interval for the true proportion is given by the following formula:
Replacing the info given we got:
And if we convert this interval into % we got (47.615%, 58.385%)
Part b
For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than most students at PCC own a car
6.83 with the 3 repeating
41 / 6 = 6.8333...
1^2 = 1
6.83 x 1 = 6.83
3. x: 180-99 = 81º (angles on a straight line equals 180)
y: 115-81 = 34º (exterior angle is sum of opposite interior angles)
4. y: 180-64 = 116 (angles on a straight line equals 180)
x: 126º
two steps
angles on straight line equals 180: 180-118 = 62º
exterior angle is sum of opposite interior angles: 62+64 = 126º
sorry if i misread any of the numbers, let me know if i did and i'll fix it
Answer:
B) 2x^9
Step-by-step explanation:
i hope that helps