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Studentka2010 [4]
3 years ago
11

X2+2y÷2w+3z for w=2,x=5,y=8

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0
If you plug everything in you get 10+16(divided by)4+3z. 16 divided by 4 is 4. 10 plus 4 is 14 so after pemdas you have 14+3z left.
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Determine the constant of varlation for the direct variation glven. Rvaries directly with S. When S is 16, R Is 80.​
navik [9.2K]

Answer:

The constant of variation is 5.

Step-by-step explanation:

In direct variation, as y varies directly with x, the standard equation is

y = kx,

where k is the constant of variation.

In your case, we use R and S. R varies directly with S, so we have

R = kS

We know that when S = 16, R is 80, so we plug in those values and solve for k, the constant of variation.

R = kS

80 = k(16)

k = 80/16

k = 5

4 0
3 years ago
A person can pay $14 for a membership to the science museum and then go to the
tekilochka [14]

Answer:

13  visits

Step-by-step explanation:

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8 0
3 years ago
Sets L and J are defined as follows.
wlad13 [49]

Answer:

The second one:

L∪J={i,j,k,l,m,n,o}

Step-by-step explanation:

The union is the elements listed in either set.

So since l,m,n, and o are elements of set L, they will also be elements of whatever it is "unioned" with.

Since i,j,k,l and m are elements of set J, they will also be elements of whatever it is "unioned" with.

When you write the union, just be sure to include each element that occurs in either set once.

So the union of L and J is {i,j,k,l,m,n,o}.

The answer is the second one.

The intersection would actually be that upside down U thing, the ∩ symbol. The intersection of two sets is a list of elements that both sets include.  So here the intersection would just consist of the elements l amd m.

8 0
3 years ago
Read 2 more answers
If 1900 square centimeters of material are available to make a box with a square base and an open top, find the largest possible
Evgen [1.6K]

Answer:

Volume = 7969 cubic centimeter

Step-by-step explanation:

Let the length of each side of the base of the box  be A and the height of the box be H.

Area of material required to make the box  is equal to  is A^2 + 4*A*H.

A^2 + 4*A*H = 1900

 Rearranging the above equation, we get -  

`H = \frac{(1900 - A^2)}{(4*A)}

Volume of box is equal to product of base area of box and the height of the box -  

V = A*A* H

Substituting the given area we get -

\frac{A^2*(1900 - A^2)}{4A} = \frac{(1900*A - A^3)}{4}

For maximum volume

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\frac{ 1900}{4} - \frac{3*A^2}{4} = 0

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Volume of the box

= \frac{\frac{1900}{3}*(1900 - \frac{1900}{3}) }{4 * \sqrt{\frac{1900}{3} } }

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3 0
3 years ago
The graph shows the function f(x).<br><br><br><br> Which equation represents f(x)?
VLD [36.1K]

f(x)=-3(x-1)

Answered would be B.

6 0
3 years ago
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