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babymother [125]
2 years ago
5

The equation given is 4=-5/3x+11 1/3

Mathematics
1 answer:
AysviL [449]2 years ago
5 0
Step by step equation
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Determine if each equation is a linear equation.
Lady_Fox [76]

Answer:

Linear-1,2,3,6

Nin-Linear-4,5

Step-by-step explanation:

A linear equation is an equation in which the highest power of the  variable is 1.

Out of the given equations, the following are linear.

1) 5x_1 + x_2 - 7x_3 = 4

2) 5x_1 + 4.6x_2 + 12x_3 = -5

3) 3x_1 - x_3 = -5x_2 + 7

6) 6x_1 - 4x_2 + x_3 = 0

These equations on the other hand are nonlinear.

4) 3x_1x_2 + x_3 = 5

5) 4x_1^3 + x_2 = 5

No 4 contains a term which is the product of two variables therefore it is not linear.

No 5 contains a term whose highest power is 3. Such an equation is a Cubic Equation.

4 0
3 years ago
What is 5(-2/3)? And how did you get it?
babunello [35]
Multiply 5 and -2. Then divide by 3.

-10/3 = -3.33333333

This can be rounded to -3.3

Hope this helps!
4 0
3 years ago
Is my answer to question 4 correct? Only answer if you know FOR SURE!
ZanzabumX [31]

Answer:

yes it is

Step-by-step explanation:

7 0
3 years ago
128 is 74% of what number?
Hatshy [7]
74% means 0.74
"of" means "times"

So,    128 = 0.74 times (the number)

Divide each side of this equation by 0.74 :

128/0.74 = the number

<em>172.973</em> (rounded) = the number
8 0
3 years ago
Read 2 more answers
What is the image point of (-12, -8) after the transformation R270° 0 D. ?
Gennadij [26K]

Given:

The point is (-12,-8).

Rule of transformation is R_{270^\circ}\circ D_{\dfrac{1}{4}}.

To find:

The coordinates of image after transformation.

Solution:

According to the rule of transformation R_{270^\circ}\circ D_{\dfrac{1}{4}}, first the point is dilated by factor \dfrac{1}{4} with origin as center of dilation after that it was rotated 270 degrees anticlockwise.

If a point is dilated by factor \dfrac{1}{4} with origin as center of dilation, then

(x,y)\to \left(\dfrac{1}{4}x,\dfrac{1}{4}y\right)

(-12,-8)\to \left(\dfrac{1}{4}(-12),\dfrac{1}{4}(-8)\right)

(-12,-8)\to \left(-3,-2\right)

If a point is rotated 270 degrees anticlockwise, then

(x,y)\to (y,-x)

(-3,-2)\to ((-2),-(-3))

(-3,-2)\to (-2,3)

Therefore, the coordinates of image after transformation are (-2,3).

3 0
3 years ago
Read 2 more answers
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