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Blababa [14]
3 years ago
13

What do waves transfer? Question 7 options: Both matter and energy Matter Neither matter nor energy Energy plz help 29 points

Physics
1 answer:
Mars2501 [29]3 years ago
5 0

The answer is energy.

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According to Newton's second law of motion, if we we have a rigid, unchanging mass and we observe it accelerating, what must be
faltersainse [42]
A. a force is being applied to the mass
4 0
3 years ago
Read 2 more answers
Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius
olasank [31]

Answer:

v₂ = 5131.42 m/s

Explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ =  84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

            v = \sqrt{\dfrac{GM}{r}}

     so,

            v \alpha \dfrac{1}{\sqrt{r}}

now,

            \dfrac{v_1}{v_2} =\sqrt{\dfrac{r_2}{r_1}}

            \dfrac{v_2}{4800} =\sqrt{\dfrac{8\times 10^7}{7 \times 10^7}}

                v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s

7 0
3 years ago
How many electrons will there be in 5 coulombs of charge?
zysi [14]
There's no physics or electronics to this question.
It's just arithmetic.

The last part of the question TELLS you how many 'coulombs per electron'.

If you just flip that fraction (divide ' 1 ' by it, take its reciprocal), then
you'll have 'electrons per coulomb',  and 5 of those will answer the question.

I got 31,250,000,000,000,000,000 .  I could be wrong.  You should check it.
7 0
4 years ago
A power plant generates 150 MW of electrical power. It uses a supply of 1000 MW from a geothermal source and rejects energy to t
marissa [1.9K]

Answer:

- the power to the air is 850 MW

- mass flow rate of the air is 84577.11 kg/s

Explanation:

Given the data in the question;

Net power generated; W_{net = 150 MW

Heat input; Q_k = 1000 MW

Power to air = ?

For closed cycles

Power to air Q₀ = Heat input; Q_k - Net power generated; W_{net

we substitute

Power to air Q₀  = 1000 - 150

Q₀ = 850 MW

Therefore,  the power to the air is 850 MW

given that ΔT = 10 °C

mass flow rate of air required will be;

⇒ Q₀ / CpΔT

we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K

we substitute

⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]

⇒ ( 850 × 10³ ) / 10.05

⇒ 84577.11 kg/s

Therefore, mass flow rate of the air is 84577.11 kg/s

3 0
3 years ago
Table is in the picture. and will mark brainstest.
QveST [7]
B. A copper wire with rubber insulation
8 0
3 years ago
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