Answer:
v₂ = 5131.42 m/s
Explanation:
given,
radius of the planet = r₁ = 9.00×10⁶ m
mass of the satellite = m₁ = 68 Kg
orbital radius = r₁ = 8 x 10⁷ m
orbital speed = v₁ = 4800 m/s
mass of second satellite = m₂ = 84.0 kg
orbital radius = r₂ = 7.00×10⁷ m
orbital speed of second satellite = v₂ = ?
using orbital speed of satellite

so,

now,


v₂ = 5131.42 m/s
The orbital speed of second satellite is equal to v₂ = 5131.42 m/s
There's no physics or electronics to this question.
It's just arithmetic.
The last part of the question TELLS you how many 'coulombs per electron'.
If you just flip that fraction (divide ' 1 ' by it, take its reciprocal), then
you'll have 'electrons per coulomb', and 5 of those will answer the question.
I got 31,250,000,000,000,000,000 . I could be wrong. You should check it.
Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated;
= 150 MW
Heat input;
= 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input;
- Net power generated; 
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s
B. A copper wire with rubber insulation