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galben [10]
3 years ago
8

What type of speed looks at a particular point in time?

Physics
1 answer:
bearhunter [10]3 years ago
4 0
The answer is D because instantaneous means at a particular point in time
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How many excess electrons are on a ball with a charge of -1.4944 10-16 C?
agasfer [191]

Answer:

There are 934 excess electrons on the ball with charge -1.4944*10^(-16).

Step-by-Step Explanation:

A ball will usually be neutral and have no charge on it.

If it is negatively charged, it means there are excess electrons on it.

If we know the charge on the ball, we can count the excess no. of electrons.

We know that the charge on the ball = c = -1.4944*10^-16

Charge of one electron = e = 1.6*10^-19

Charge of n electrons on the ball = ne = c

⇒ n = c/e

n = (-1.4944*10^-16)/(1.6*10^-19)

n = 934 electrons

7 0
3 years ago
Which is true about forensic testing? Forensic scientists must accurately interpret test results Evidence testing is no longer r
Nana76 [90]

Answer:

Forensic scientists must accurately interpret test results

Explanation:

Misinterpreting test results could mean someone being falsely accused of a crime which you would want to avoid.

5 0
2 years ago
The movement of water between the atmosphere, land, oceans, and even living things makes up the water cycle. Precipitation is on
Anna [14]

I have no idea

Explanation:

4 0
3 years ago
How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it
Oksi-84 [34.3K]

Answer:

Explanation:

more the density , more will be the buoyant force acting on it , less the density less will be the buoyant force acting on it. This is why people float in dead sea and sink in other seas

5 0
3 years ago
I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app
Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

6 0
3 years ago
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