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djverab [1.8K]
3 years ago
15

Table is in the picture. and will mark brainstest.

Physics
1 answer:
QveST [7]3 years ago
8 0
B. A copper wire with rubber insulation
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Taking force , length and time as fundamental quantity , find the dimensional formula for density​
Law Incorporation [45]

Answer:

fundamental formula for density = Kg/m³

Explanation:

density = mass/volume

5 0
3 years ago
"An object at rest starts accelerating. If it is going 120 m/s after traveling 202 meters, how quickly did it speed up?"
Marizza181 [45]

Answer:

this is just a guess bc i only looked at it for 5 seconds but i think 150 m/s

4 0
3 years ago
In another solar system is planet Driff, which
Fed [463]

Answer:

It is (1/5)th as much.

Explanation:

If we apply the equation

F = G*m*M / r²

where

m = mass of a man

M₀ = mass of the planet Driff

M = mass of the Earth

r₀ = radius of the planet Driff

r = radius of the Earth

G = The gravitational constant

F = The gravitational force on the Earth

F₀ = The gravitational force on the planet Driff

g = the gravitational acceleration on the surface of the earth

g₀ = the gravitational acceleration on the surface of the planet Driff

we have

F₀ = G*m*M₀ / r₀² = G*m*(5*M) / (5*r)²    

⇒  F₀ = G*m*M / (5*r²) = (1/5)*F

If

F₀ = (1/5)*F

then

W₀ = (1/5)*W   ⇒  m*g₀ = (1/5)*m*g   ⇒   g₀ = (1/5)*g

It is (1/5)th as much.

5 0
3 years ago
The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
Read 2 more answers
How is newtons third law of motion demonstrated on a roller coaster?
butalik [34]
<span>Newton's Third Law of Action-Reaction is that for each and every action that happens, there is an equal and opposite reaction to it. In the scenario of a roller coaster, this is when you push down on the seat of the roller coaster as it flies along and the seat pushes back against you.</span>
8 0
3 years ago
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