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3 years ago

Which two criteria are least important for engineers to consider when

Physics

2 answers:

Zepler [3.9K]3 years ago

7 0

Answer:

B C & D

Explanation:

should make you money, time well spent no time lost.

lara31 [8.8K]3 years ago

3 0

Answer:

B and C

Explanation: i looked at the test and i got it right

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cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your

sp2606 [1]

We have that the time in seconds, minutes, and hours is

$t=1.083*10^{-4}s$

$T_{min}=1.805*10^{-6}min$

$T_{hours}=3.0083*10^{-8}hours$

From the Question we are told that

Velocity $v=13.0m/s$

Distance $d=120 km$

Generally the equation for the Time is mathematically given as

$t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s$

Therefore

$T_{min}=1.083*10^{-4}s/60$

$T_{min}=1.805*10^{-6}min$

And

$T_{hours}=T_{min}/60$

$T_{hours}=3.0083*10^{-8}hours$

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brainly.com/question/12319416?referrer=searchResults

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3 years ago

A hydrogen bomb has a diameter of about 10nm express this in meters

GenaCL600 [577]

1 Nautical metre=1852 metres
10×1852
=18520 metres

3 0

3 years ago

What happens to the magnitude of the momentum of an object if the mass of the object halved?<br>

nekit [7.7K]

Answer:

Momentum is directly proportional to velocity. If momentum of an object is doubled , but its mass does not increase (so velocity remains below the speed of light) then its velocity is doubled. If the velocity is doubled, then the kinetic energy increases by four times.

Explanation:

Hope it is helpful....

8 0

3 years ago

If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is

zysi [14]

Answer:

$q_2=2.47\times 10^{-4}\ C$

Explanation:

The charge on one object, $q_1=9.9\times 10^{-5}\ C$

The distance between the charges, r = 0.22 m

The force between the charges, F = 4,550 N

Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

$F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C$

So, the charge on the other sphere is $2.47\times 10^{-4}\ C$ .

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3 years ago

A scientist studies the effect of adding different amounts of salt on the boiling point of water. He places his results in the g

den301095 [7]

The amounts are the independent boiling water is dependent

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3 years ago

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