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valentinak56 [21]
3 years ago
11

The Nut Shoppe sells walnuts for $4.00 a pound and cashews for $7.00 a pound. How many pounds of cashews should be mixed with 10

pounds of walnuts to obtain a mixture that sells for $5.50 a pound?
Mathematics
1 answer:
Anton [14]3 years ago
7 0

Answer: He sold 10 pounds of cashews .

Step-by-step explanation:

Since we have given that

Selling price of walnuts = $4.00 a pound

Selling price of cashews = $7.00 a pound

Number of pounds of walnuts = 10

Let number of pounds of cashew be x

Total price at which he sold a mixture = $5.50

According to question,

10\times 4+x\times 7=(10+x)\times 5.50\\\\40+7x=55+5.5x\\\\7x-5.5x=55-40\\\\1.5x=15\\\\x=\frac{15}{1.5}\\\\x=10

Hence, he sold 10 pounds of cashews .

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liubo4ka [24]

Answer:

3 + 4.50g \leq 25

g\leq 4

Step-by-step explanation:

25 - 3 is 22. 22 divided by 4.50 is a decimal. But it rounds down to 4. So the most amount of games Tristan can play is 4.

Hope it helps!

6 0
3 years ago
Does anyone know this??
I am Lyosha [343]
The answer is A 5*3=15 it must be an equal proportion so 6*x =15
4 0
2 years ago
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Find Y (pic attached) (i’ll mark brainliest)
Nadya [2.5K]

Answer:

4y - 4 = 60

4y = 64

Y = 16

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5 0
2 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
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