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harkovskaia [24]
3 years ago
5

How do you know if a problem is extraneous or not?

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:


Step-by-step explanation:

An extraneous solution is a solution that's not really a solution.  In other words, you work out the problem and you obtain a solution.  Then you test your solution by plugging in your solution to the formula given, if the result is false then it's considered an extraneous solution.


For example, if you're solving for time it took for a football to reach the ground after somebody threw it, you would obtain two answers for time.  These time answers are negative time and positive time, well the negative time makes no sense since it's before you threw the ball so we would consider that negative solution to be extraneous.

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

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Write an integer for a profit of 12
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Which angle is congruent to BGC?
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