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harkovskaia [24]
3 years ago
5

How do you know if a problem is extraneous or not?

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:


Step-by-step explanation:

An extraneous solution is a solution that's not really a solution.  In other words, you work out the problem and you obtain a solution.  Then you test your solution by plugging in your solution to the formula given, if the result is false then it's considered an extraneous solution.


For example, if you're solving for time it took for a football to reach the ground after somebody threw it, you would obtain two answers for time.  These time answers are negative time and positive time, well the negative time makes no sense since it's before you threw the ball so we would consider that negative solution to be extraneous.

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Fred was paid $36.00 for working 4 hours. how much is he paid per hour?​
bezimeni [28]
He would get paid 9 dollars and hour
3 0
3 years ago
HELP PLEASE!!!
True [87]

Answer:

The graph of f(x) is shifted k units to the right of the graph of g(x).    

Step-by-step explanation:

Given the function  and  where k <0.

As, horizontal depends on the value of x and are when

g(x)=f(x+h)   graph shifted to left.

g(x)=f(x-h)    graph shifted to right.

Now, given

But here k is negative, when k is considered positive then f(x) becomes

⇒ The graph of f(x) is shifted k units to the right of the graph of g(x).

Correct option is B.

6 0
3 years ago
What is the manipulative inverse of -1/3
Mkey [24]

Answer:

1/3

Step-by-step explanation:

The inverse is the opposite of a number.

6 0
3 years ago
Read 2 more answers
You choose a marble at random from a bag containing 8 brown marbles 6 yellow marbles and one purple marble. You replace the marb
Andrej [43]
Pick 1: 6 yellow out of 15 total marbles = 6/15 = 2/5
Pick 2: 6 yellow out of 15 total marbles = 6/15 = 2/5

Pick 1 AND Pick 2
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5 0
3 years ago
Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is a
morpeh [17]
We have that

the expression 2f + 4f + 2 – 3-------> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
6 0
4 years ago
Read 2 more answers
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