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forsale [732]
3 years ago
12

Guys I need help in this ​

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

For Table 1, the answer is Not Proportional (B).

For Table 2, the answer is proportional, with y is 3 times x.

Step-by-step explanation:

In table 1, for the first value of x, y is equal to 32, and 32/8 is 4. Remember that, because in order for x and y to be proportional, y/x always has to equal the same number. Let's try the next value. 50/10 = 5, which is obviously not 4, so in table 1, x and y are not proportional. (we didn't even have to try the last one, yay!!!)

In table 2, for the first values 21 and 7, 21/7 is 3. 30/10, the second values, also equals to 3, and so does the last, 39/13 = 3. Therefore, in table 2, x and y are proportional, and y is 3 times x. (7 * 3 = 21, 10 * 3 = 30, and 13 * 3 = 39.)

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Answer:

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Step-by-step explanation:

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3 years ago
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Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Answer:

I hope this helps

Step-by-step explanation:

give me braineast

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I have solved some examples in the picture

If anything is unclear let me know.

:)

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