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blagie [28]
3 years ago
10

Over the summer, for every 12 okra seeds Dana planted, 7 grew into plants. If he planted 144 okra seeds, how many grew into plan

ts?
A.
69
B.
84
C.
139
D.
247
Mathematics
1 answer:
professor190 [17]3 years ago
5 0

Answer:

If Dana planted 144 okra seeds, 84 of those seeds grew into plants.

Explanation:

Image below.

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G(x)=2x^2+3x+6<br> find g(p+3)
hichkok12 [17]
We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33
5 0
3 years ago
Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H.Which sequence of
Tasya [4]

Answer:

the answer is A

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
The coffee Lily likes is composed of 97.3% water and 2.7% cocoa. The coffee John likes is composed of 96% water and 4% cocoa. Ho
mestny [16]

30 ounces of the coffee John likes consists of

  • 0.96\cdot30=28.8 ounces of water
  • 0.04\cdot30=1.2 ounces of cocoa

To this mixture we're adding x ounces of water, so that the new mix has a total volume of 30+x ounces and matches the composition of the coffee Lily likes. This means it would consist of

  • 0.973\cdot(30+x)=28.8+x ounces of water
  • 0.027\cdot(30+x)=1.2 ounces of cocoa (same amount of cocoa as before because pure water is being added)

Solve for x:

0.973(30+x)=28.8+x\implies29.12+0.973x=28.8+x

\implies0.39=0.027x

\implies x\approx14.4

###

Just to confirm: the new mixture consists of

  • 28.8+14.4=43.2 ounces of water
  • 1.2+0=1.2 ounces of cocoa

giving a total volume of 43.2+1.2=44.4 ounces of coffee, and \dfrac{43.2}{44.4}\approx0.973, as required.

4 0
3 years ago
HELP PLS LMK IF U CANT READ IT AND I WILL TYPE IT
GenaCL600 [577]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

5 0
3 years ago
Read 2 more answers
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