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3 years ago

How many mL are in 7.3 dL?

Chemistry

1 answer:

Arte-miy333 [17]3 years ago

8 0

Answer:

730 mL which is .73 L

Explanation:

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Students are studying the effects of beach pollution by counting populations of seagulls at two different beach locations. One l

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The weather/wind direction

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3 years ago

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

Neko [114]

Answer:

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

100 mg/mL?

a. 25

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Explanation:

if mali po I'm so sorry

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3 years ago

When are the products of an equilibrium reaction favored? When the reaction is endothermic. When the equilibrium constant is lar

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Product are favored at ...

example 2A + 3B = 5C + D if reaction is exothermic ....delta H = NEGATIVE)

A decrease in temperature favors the forward reaction (more product formed)
as heat is considered as a product

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decreasing concentration of product will cause a disturbance in equilibrium position....and reaction will restore its equilibrium by shifting to the right

(I believe its like this)

3 0

3 years ago

Read 2 more answers

Determine the number of significant figures in 478 cm

Grace [21]

Answer:

There are 3 significant figures on this one.

3 0

3 years ago

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = $5.61*10^-^5$

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3 years ago