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3 years ago

Who else just copy and pastes the questions from edge?

Chemistry

1 answer:

Kobotan [32]3 years ago

5 0

Answer:

haha

Explanation:

yea because my phat a22 is to lazy

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Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide soluti

NeX [460]

Answer: The molarity of the base solution is 0.22 M.

Explanation:

According to the neutralization law,

$n_1M_1V_1=n_2M_2V_2$

where,

$M_1$ = molarity of $HCl$ solution = 0.1994 M

$V_1$ = volume of $HCl$ solution = 38.87 ml

$M_2$ = molarity of $NaOH$ solution = ?

$V_2$ = volume of $NaOH$ solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml

$n_1$ = valency of $HCl$ = 1

$n_2$ = valency of $NaOH$ = 1

$1\times 0.1994\times 38.87=1\times M_2\times 35.02$

$M_2=0.22M$

Therefore, the molarity of the base solution is 0.22 M.

8 0

4 years ago

Read 2 more answers

______help in increasing rates of reactions

RideAnS [48]

Answer:

Catalysts help in increasing rates of reactions

4 0

3 years ago

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How do you know how many valence electrons are in a molecule?

telo118 [61]

1. by making a atomic configuration
2.by making a table of shells of k.l.m.n....
that's all

4 0

4 years ago

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Which of the following hypotheses cannot be tested using the scientific method?

lara31 [8.8K]

Answer:

<h2>The bombing of Hiroshima ended World War II.</h2>

Explanation:

[The scientific method includes these steps:

Observation

Hypothesis

Experimentation

Data Analysis

Conclusion]

The first two Hypothesis can be tested with the scientific method, you cannot go back in time and observe or experiment with the bombing of Hiroshima to deduce whether or not it ended World War II.

8 0

3 years ago

2. Nitrogen has two naturally occurring

kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0

3 years ago