Sum of all interior angles of a polygon
180( n - 2) where n = number of sides in the polygon
now, if n = 19, the polygon has 19 sides, then 180( 19 - 2)
Step-by-step explanation:
sin∅=-3/4 in 4 quadrant which sine is negative there
using soh cah toa
sin=opp/hyp
where our opp=-3 and our hyp=4
using pythagoras theorem
hyp²=opp²+adj²
(4)²=(-3)²+adj²
16=9+adj²
16-9=adj²
adj²=7
adj=√7
from soh cah toa
cos∅=adj/hyp
cos∅=√7/4
Answer:
none of the above
Step-by-step explanation:
You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.
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You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
Filling in the given points, we get ...
y = (3 -1)/(2 -4)·(x -4) +1
y = 2/(-2)(x -4) +1 . . . . . simplify a bit
y = -x +4 +1 . . . . . . . . . simplify more
y = -x +5 . . . . . . . . . . . slope-intercept form