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Reil [10]
3 years ago
14

Solve for n: a= p(1+nr)

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0
N=    1     a          this is the answer hope i helped
     -  _ +  _
         r      pr
mart [117]3 years ago
4 0
This problem involves switching around the variables a lot

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-3x=6x + 2 solve for x
AnnyKZ [126]

Answer:

Step-by-step explanation:

6x+3x= -2

9x= -2

x= -2/9

8 0
3 years ago
Read 2 more answers
  A polygon that has all sides the same measure and all angles the same measure is called what?        A. Convex polygon   B. Co
Schach [20]
<span>D. Regular polygon.

</span>A polygon that has all sides the same measure and all angles the same measure is called Regular polygon.

Hoped I helped!
8 0
4 years ago
Identify all of the following solutions of (square root of x+8)-6 =X
seropon [69]
Square root (x + 8) -6 = x
square root (x + 8)  = x -6
x^2 + 16x  + 64 = x^2 -12x + 36

28x = 48
x =  <span> <span> <span> 1.7142857143 </span> </span> </span>

None of the above

8 0
3 years ago
A company rents out 17 food booths and 22 game booths at the county fair. The fee for a food booth is $175 plus $10 per day. The
GrogVix [38]

Answer:

<em>Ct = 4075 + 368d</em>

Step-by-step explanation:

<u>Function Models</u>

A company rents out food booths and game booths at the county fair.

For a food booth, the company charges a fixed fee of $175 and a variable fee of $10 per day. If d is the number of days, then the charges for a food booth are:

Cf = 175 + 10d

Similarly, the company charges $50 plus $9 per day for a game booth, thus the total charges are:

Cg = 50 + 9d

If all the booths are rented for the entire time, the total amount the company is paid for 17 food booths and 22 game booths is:

Ct = 17Cf + 22Cg

Substituting:

Ct = 17(175 + 10d) + 22(50 + 9d)

Operating:

Ct = 2975 + 170d + 1100 + 198d

Simplifying:

Ct = 4075 + 368d

8 0
3 years ago
Find the area of the figure above. use 3.14 for π. do not round your answer
professor190 [17]

Answer:

Step-by-step explanation:

Alright, lets get started.

This is the combination of three figures semi circle, rectangle and triangle.

We will find the area of each figure and will add them.

The radius of the circle is half of the diameter, so radius is 6.

Area of semi circle will be : \frac{1}{2} \times 3.14 \times 6^2

Area of semi circle is : 56.52

Area of rectangle is: length \times width

So, area of rectangle is:40\times 12=480

Area of triangle is : \frac{1}{2}\times base\times height

So, area of triangle is :\frac{1}{2} \times 12\times 5=30

Adding all these three areas, the area of above figure will be:

[tex]Area = 56.52+480+30

Hence Area is 566.52............... Answer

6 0
3 years ago
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