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andreev551 [17]
3 years ago
11

Help please !!!!!!!!!!!!!!!!!!!

Physics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

Hi there!

The answer to this question is the first choice: Xe 138 (top), 54 (bottom)

Because on the left side it adds up to 240 (top) and 94 (bottom)

and the right side adds up to 102 (top) and 40 (bottom)

to equal both sides, you need 138 more to get 240 on the top and 54 on the bottom to get 94. then you use the bottom number 54, to see what element it is and Xenon is the answer.

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umka21 [38]

Answer:

150N

Explanation:

To find the force applied remember that force equals to Mass multiply by the Acceleration.

F=Ma

=30*5

=150N

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3 years ago
A bee beats its wings approximately 184 times per second. what is its wave period?
sergejj [24]

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An atom with an imbalance of electrons to protons is
alexdok [17]
<h2>Answer: Ion </h2>

An ion is an atom that is electrically charged by <u>gaining or losing one or more electrons. </u>

To understand it better:

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In this sense, there are two types of ions:

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7 0
4 years ago
If R = 12 cm, M = 520 g, and m = 20 g (below), find the speed of the block after it has descended 50 cm starting from rest. Solv
timofeeve [1]

Answer:

v = 0.84 m/s

Explanation:

given,

R = 12 cm

M (mass of pulley )= 520 g

m  (mass of block)=  20 g

s = 50 cm = 0.5 m

using conservation of energy

Potential energy = Kinetic energy

 m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2

   I_{disk}= \dfrac{1}{2}MR^2  and v = r ω

 m g h = \dfrac{1}{2}mv^2 + \dfrac{1}{2}(\dfrac{1}{2}MR^2)(\dfrac{v}{R})^2

 m g h = \dfrac{1}{2}mv^2 +\dfrac{1}{4}Mv^2

 m g h = \dfrac{1}{2}v^2(m +\dfrac{1}{2}M)

 v=\sqrt{\dfrac{2mgh}{m + 0.5 M}}

 v=\sqrt{\dfrac{2\times 0.020 \times 9.8 \times 0.5}{0.02 + 0.5\times 0.52}}

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5 0
3 years ago
A frictionless piston-cylinder device contains 4.5 kg of nitrogen at 110 kPa and 200 K. Nitrogen is now compressed slowly accord
pochemuha

Answer:

427.392 kJ

Explanation:

m = Mass of gas = 4.5 kg

Initial temperature = 200 K

Final temperature = 360 K

R = Mass specific gas constant = 296.8 J/kgK

\gamma = Specific heat ratio = 1.5

Work done for a polytropic process is given by

W=\frac{mR\Delta T}{1-\gamma}\\\Rightarrow W=\frac{4.5\times 296.8(360-200)}{1-1.5}\\\Rightarrow W=-427392\ J\\\Rightarrow W=-427.392\ kJ

The work input during the process is -427.392 kJ

3 0
4 years ago
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