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timama [110]
3 years ago
13

ONLY ANSWER IF YOU KNOW FOR SURE PLEASE :)

Physics
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

Question one is b, Question two is b, and question three is b, im pretty positive that what it is

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I'm working from a study guide and I got a question asking:
Harlamova29_29 [7]

you need to use hours to make it easy to convert to m/s. Change 15 minutes to hours

Note distance is in km so change the time to hours to get km/hour

1 hour = 60mins so 15 minutes will be 0.25 hours

10/0.25 = 40 km/ hour

To change that to m/second, change km to meters and hour to second

it will be (40x1000) meters /3600seconds

11.1111 m/s

8 0
3 years ago
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Please answer this question asap
ICE Princess25 [194]

Answer:

The magnetic compass shows no deflection.

Explanation:

  • When a magnetic compass is placed on a current-carrying conductor, the compass needle shows deflection.
  • When the direction of the current is reversed, the needle deflects in the opposite direction.
  • This is due to the fact that the current-carrying conductor generates a magnetic field around it.
  • If the direction of the current is reversed, the magnetic polarization changes.
  • This phenomenon was first noticed by Oersted, and later it helped to develop electromagnetism.
6 0
4 years ago
All of the following are benefits of statistics except that it __________. A. increases knowledge B. promotes change C. creates
erastovalidia [21]
C. creates biases
this is the only answer that would be a disadvantage. 
5 0
3 years ago
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Hãy nêu sự tương tự giữa công của lực điện trong trường hợp này với công của trọng lực.​
statuscvo [17]

Answer:

tốt ý bạn là gì?

Explanation:

6 0
3 years ago
A 12.70 g bullet has a muzzle velocity (at the moment it leaves the end of a firearm) of 430 m/s when rifle with a weight of 25.
Norma-Jean [14]

Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same  provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\

assume the bullet goes to right side and the gravitational acceleration =10 ms^{-2}

so now the weight of the rifle=\frac{25}{10}  

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}

this is a negative velocity to the right side. that means the rifle recoils to the left side

3 0
3 years ago
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