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HACTEHA [7]
3 years ago
14

Find the product of the complex number: 4 -3 i and its conjugate. 25 -7 7

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

find the product of the complex number 3-3 i and its conjugate

25-7-7=11

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They both can hold a certain amount
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Justin has $7.50 more then Eva, and Emma has $12 less than Justin. Together, they have a total of $63.00. How much money does ea
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To make it easier, lets say Justin = J, Eva = E, and Emma = M. Then, J = E + 7.50 M = J -12 J + E + M = 63 You can substitute for M in the third equation using the second equation, and you get: J + E + J - 12 = 63 Clean it up a little bit and you get: 2J + E = 75 You know J = E + 7.50, so substitute that for J and you get: 2(E + 7.50) + E = 75 2E + 15 + E = 75 3E + 15 = 75 3E = 60 E = 20 ; meaning that Eva has $20. Justin has $7.50 more than Eva, so he has $27.50. Emma has $12 less than Justin, so Emma has $15.50. Double check your answer by making sure they all add up to 63, which they do.
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a ribbon is 12.3 feet long. another is 3.12 feet shorter than it. what is the total length of the two ribbons?
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What type of correlation would you expect between the number of minutes a candle burns and the height of the candle
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Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
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