Answer:
It's comparative
compare means to find the similarities and differences of two or more objects.
Explanation:
Answer:
Day and night on Earth are equal.
Explanation:
Vernal means fresh or new like the spring. The vernal equinox, because it signals the beginning of spring. On this day, the Sun is exactly above the Equator and day and night are of equal length. In the northern hemisphere, the vernal equinox is around March 20 or 21 when the Sun crosses the celestial equator going north while in the southern hemisphere, the vernal equinox is around September 22 or 23 when the Sun moves south across the celestial equator.
Answer:
a
b
Explanation:
From the question we are told that
The position of the column of mercury in the barometer is \
The density of mercury is
Generally the pressure of the atmosphere at that column is mathematically represented as
=>
=>
Generally the atmospheric pressure at sea level (Generally the pressure before the change in level of the mercury column) is
Generally the change in air pressure is mathematically represented as
=>
=>
Generally the height which the column will rise to is mathematically evaluated as
Here is the density of water with value
So
=>
Answer:
Rounded to three significant figures:
(a) .
(b) .
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let denote a natural number (.) In a double-split experiment of a monochromatic light:
- A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: .
- Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: .
<h3 /><h3>Maxima</h3>
The path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where in .
The path difference increases while moving on the screen away from the center. The first order maximum is at where .
Similarly, the second order maximum is at where . For the light in this question, at the second order maximum: .
- Central maximum: , such that .
- First maximum: , such that .
- Second maximum: , such that .
<h3>Minima</h3>
The dark fringe closest to the center of the screen is the first minimum. at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. at that point.
- First minimum: , such that .
- Second minimum: , such that .
For the light in this question, at the second order minimum: .