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3 years ago

A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity

Physics

2 answers:

lora16 [44]3 years ago

5 0

Answer:

$\displaystyle 9,1829787234\:m/s$

Explanation:

$\displaystyle \frac{[0,39][166]}{7,05} = \frac{7,05v}{7,05} \\ \\ 9,1829787234 ≈ v$

I am joyous to assist you anytime.

dimaraw [331]3 years ago

4 0

Answer:

9.17 m/s

Explanation:

Impulse = change in momentum

FΔt = mΔv

(166 N) (0.39 s) = (7.06 kg) Δv

Δv = 9.17 m/s

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Answer:

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4 years ago

It is estimated that uranium is relatively common in the earth's crust, occurring in amounts of 4 g / metric ton. A metric ton i

timama [110]

Answer:

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3 years ago

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2 years ago

Read 2 more answers

a driver is going at 120km h and sees a barrier 60.0 m ahead it takes 5secounds to apply the brakes and decelerates at 12m does

Soloha48 [4]

Answer:

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3 years ago

A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.

Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

$F=mg$

$\dfrac{mv^2}{r}=mg$

$\dfrac{v^2}{r}=g$

$v=\sqrt{rg}$

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

$v=\sqrt{250\times9.8}$

$v=49.49\ m/s$

Hence, The speed of space station floor is 49.49 m/s.

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3 years ago