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Neporo4naja [7]
3 years ago
15

A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity

Physics
2 answers:
lora16 [44]3 years ago
5 0

Answer:

\displaystyle 9,1829787234\:m/s

Explanation:

\displaystyle \frac{[0,39][166]}{7,05} = \frac{7,05v}{7,05} \\ \\ 9,1829787234 ≈ v

I am joyous to assist you anytime.

dimaraw [331]3 years ago
4 0

Answer:

9.17 m/s

Explanation:

Impulse = change in momentum

FΔt = mΔv

(166 N) (0.39 s) = (7.06 kg) Δv

Δv = 9.17 m/s

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A horizontally oriented pipe has a diameter of 5.8 cm and is filled with water. The pipe draws water from a reservoir that is in
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Answer:

v₂ = 97.4 m / s

Explanation:

Let's write the Bernoulli equation

         P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Index 1 is for tank and index 2 for exit

We can calculate the pressure in the tank with the equation

        P = F / A

Where the area of ​​a circle is

       A = π r²

E radius is half the diameter

      r = d / 2

      A = π d² / 4

We replace

    P = F 4 / π d²2

    P₁ = 397 4 /π  0.058²

    P₁ = 1.50 10⁵ Pa

The water velocity in the tank is zero because it is at rest (v1 = 0)

The outlet pressure, being open to the atmosphere is P1 = 1.13 105 Pa

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We replace on the first occasion

   P₁ = P₂ + ½ ρ v₂²

  v₂ = √ (P1-P2) 2 / ρ

  v₂ = √ [(1.50-1.013) 10⁵ 2/1000]

  v₂ = 97.4 m / s

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