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Neporo4naja [7]
3 years ago
15

A force of 166 N acts on a 7.05-kg bowling ball for .39 seconds . What is the bowling balls change in velocity

Physics
2 answers:
lora16 [44]3 years ago
5 0

Answer:

\displaystyle 9,1829787234\:m/s

Explanation:

\displaystyle \frac{[0,39][166]}{7,05} = \frac{7,05v}{7,05} \\ \\ 9,1829787234 ≈ v

I am joyous to assist you anytime.

dimaraw [331]3 years ago
4 0

Answer:

9.17 m/s

Explanation:

Impulse = change in momentum

FΔt = mΔv

(166 N) (0.39 s) = (7.06 kg) Δv

Δv = 9.17 m/s

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A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the c
puteri [66]

Correct question:

A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?

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the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

Explanation:

Given;

length of solenoid, L= 0.35 m

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The number of turns per meter for the solenoid is calculated as follows;

B =\mu_o  I(\frac{N}{L} )\\\\B =  \mu_o  I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m

Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

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3 years ago
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