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3 years ago

Plz help! ill mark brainiest

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Answer:

part a) linear, linear

part b) function #1

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What is the slope of the line that passes through the points ( 10 , − 6 ) (10,−6) and ( 8 , − 16 ) ? (8,−16)?

GaryK [48]

Answer:

Step-by-step explanation:

-16-(6)

over

8-10

slope= -10/-2

simplify:

5/1=5

4 0

3 years ago

Someone pls help me it would be amazing thank u a lot

Ivenika [448]

Answer:

36.87°

Step-by-step explanation:

With reference angle C

perpendicular (p) = 27

base(b) = 36

Now

Tan C = p/b

Tan C = 27/36

C = tan ^-1( 27/36)

= 36.87°

Hope it helps

6 0

3 years ago

Read 2 more answers

It is -15° ourside and it increases 2° per hour what is the temperature adter 8 hours

neonofarm [45]

1°, because -15° + (2° × 8 hours) = 1°

7 0

3 years ago

Read 2 more answers

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

Using the Triangle Sum Theorem, find x and the missing angles (2x +1) (5x +5) x= Angle (2x+1) = Angle (5x+5) =

Arte-miy333 [17]

Answer:

x = 12

(2x + 1)° = 25°

(5x + 5)° = 65°

Step-by-step explanation:

By the property of a triangle,

Sum of all angles of a triangle is 180°

In the given right triangle,

(2x + 1)° + 90° + (5x + 5)°= 180°

7x + 96 = 180

7x = 180 - 96

x = $\frac{84}{7}$

x = 12

Angle (2x + 1)° = 2(12) + 1 = 25°

Angle (5x + 5)° = 5(12) + 5 = 65°

Therefore, all three angles of the right triangle are 25°, 90° and 65°.

4 0

3 years ago