Your answer is the first option, 8.0. You can find this by using the sine rules for sides, so:
10/sin(90) = x/sin(53)
× sin(53)
7.98 = x
And 7.98 rounded to the nearest tenth is 8.0.
I hope this helps!
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
Let s equal the number of shirts she can buy
140 > $28.50 + $20.75s
111.50 > 20.75s
5.37 > s
so we round down. she can buy 5 shirts, plus the one dress and she would spend less than $140
Answer:
take the answer on picture which I attached with your question
Answer: ![1,270in^2](https://tex.z-dn.net/?f=1%2C270in%5E2)
Step-by-step explanation:
The surface area of a rectangle can be calculated with:
![Area_{rectangle}=lenght*width](https://tex.z-dn.net/?f=Area_%7Brectangle%7D%3Dlenght%2Awidth)
The surface area of a trapezoid can be calculated with:
![Area_{trapezoid}=\frac{height}{2}(Larger\ base+Smaller\ base)](https://tex.z-dn.net/?f=Area_%7Btrapezoid%7D%3D%5Cfrac%7Bheight%7D%7B2%7D%28Larger%5C%20base%2BSmaller%5C%20base%29)
Calculate the area of the base, wich is a rectangle:
![A_{1}=(34in)(15in)=510in^2](https://tex.z-dn.net/?f=A_%7B1%7D%3D%2834in%29%2815in%29%3D510in%5E2)
There are two equal rectangles, therefore, multiply the area of any of them by 2:
![A_{2}=2(15in)(13in)=390in^2](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2815in%29%2813in%29%3D390in%5E2)
Calculate the area of the other rectangle:
![A_{3}=(15in)(10in)=150in^2](https://tex.z-dn.net/?f=A_%7B3%7D%3D%2815in%29%2810in%29%3D150in%5E2)
There are two equal trapezoids, therefore, multiply the area of any of them by 2:
![A_4=\frac{2(5in)}{2}(34in+10in)=220in^2](https://tex.z-dn.net/?f=A_4%3D%5Cfrac%7B2%285in%29%7D%7B2%7D%2834in%2B10in%29%3D220in%5E2)
Therefore, the surface area will be the sum of all the areas calculated:
![SA=A_1+A_2+A_3+A_4\\\\SA=510in^2+390in^2+150in^2+220in^2\\\\SA=1,270in^2](https://tex.z-dn.net/?f=SA%3DA_1%2BA_2%2BA_3%2BA_4%5C%5C%5C%5CSA%3D510in%5E2%2B390in%5E2%2B150in%5E2%2B220in%5E2%5C%5C%5C%5CSA%3D1%2C270in%5E2)