So she has 400 and 500 so far.
now if she were to have an average of 2300 for the next 5 years, that means some years she made more, some she made less, but in the 5 years run, she made 2300 * 5 or 11500 total.
Neverminding the lows and highs, if we bundle up the 11500 bucks and divide by 5, that'd 2300, which is what's called the average, the average amount doesn't take into account that some numbers are higher than others, it kinda just flattens them out.
so in total she would have made 11500 in each account.
so in the account with 400, she needs 11100 more, how much will it be 1100 for the next three years on average? 11100/3 or 3700.
so if she earns 3700 each year, for the next 3 years in the account with 400 already, she'd have 11500 bucks in 5 years with an average of 2300.
now let's look at the 500 account, she needs 11000 more, how much will it be for 11000 for the next three years on average? 11000/3 or about 3666.67.
so if she earns 3666.67 each year, for the next 3 years, she'd have 11500 bucks in 5 yeas with an average of 2300.
1). F
2). T
3). F
4). F
5). F
Bet you learned a lot from this answer !
Answer:
the geometric series is a(n) = -12(3)^(n-1)
Step-by-step explanation:
"Triple" denotes multiplication by 3. Thus, the common factor here is 3.
The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.
Here, we have a(n)= (-12)(3)^(n-1) = -972.
We need to solve this for n, which represents the last term.
The first step towards solving for n is to divide both sides by -12:
3^(n-1) = 81
To solve for n-1, rewrite 81 as 3^4. Then we have:
3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.
Then we know that it is the 5th term that equals -972.
In summary, the geometric series is a(n) = -12(3)^(n-1).
