I am not exactly sure, but I am almost positive it is a spere
Answer:
.
Step-by-step explanation: Given radical expression
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and

Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.</h3>
Answer:
bad in this..............
The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.
Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation
〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0
==> <em>z</em> - 2 = 0
==> <em>z</em> = 2