Answer:
cos X = ![\frac{5}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B13%7D)
Step-by-step explanation:
simplify 15/39
The numbers that round up to 600 and have one decimal place are-
599.5
599.6
599.7
599.8
599.9
The numbers that round down to 600 and have one decimal place are-
600.1
600.2
600.3
<span>600.4
As far as numbers with more than one decimal place that round to 600, there is an infinite number. For example, 600.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000</span>0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001 rounds down to 600.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.
Answer:
The likelihood that the professor's socks matched his pants on both days is 0.5625
Step-by-step explanation:
Total no. of pair of socks = 24
No. of black pairs = 18
We are given that he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.
So, It is a case of replacement
He always wears black pants.
We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.
So ,Probability of wearing black socks on Monday = ![\frac{18}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B24%7D)
So ,Probability of wearing black socks on Tuesday =![\frac{18}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B24%7D)
So,the likelihood that the professor's socks matched his pants on both days = ![\frac{18}{24} \times \frac{18}{24}=0.5625](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B24%7D%20%5Ctimes%20%5Cfrac%7B18%7D%7B24%7D%3D0.5625)
Hence the likelihood that the professor's socks matched his pants on both days is 0.5625
Its because the power of zero is undefined
You don't need 3 equations to get a general solution. To do this use the equations x-3y-z=0 and -x+2y+0z= -3. Start out by letting z = t. Then solving those 2 equations simultaneously, your x's cancel out leaving you with -y-z=-3. But since z=t, then -y=-3+t or y=3-t. Now sub that in for y in the first equation, along with the fact that z=t to get x-3(3-t)-t = 0 and solve for x. x=9-2t. So a general solution for this would be (9-2t, 3-t, t)