Answer:
Step-by-step explanation:
∠ADC = 90°
∠ADB + ∠BDC = 90
20 + ∠BDC = 90
∠BDC = 90 - 20 = 70
∠BDC = 70°
16) ∠PSR = ∠PSQ +∠QSR
= 60 + 10
= 70
18) ∠PSR = 130
∠PSQ + ∠QSR = 130
90+ ∠QSR = 130
∠QSR = 130 - 90
∠QSR = 40
19)∠ADC = ∠ADB + ∠BDC
= 120 +20
= 140
20) ∠PSR = 125
Answer:
A
Step-by-step explanation:
in option B, you are adding the 3 pound plastic box to each cardboard box
in option A, you have 5 separate carboard packages, and one 3 pound plastic box
This [option a] is the diagram that matches the scenario given.
Think of the x's as normal numbers. Let's say the weight of each "x" is 1. [it's not I'm aware that this question is different]
if you have 5 x's, you have
1 1 1 1 1 3
<em>not </em>1+3 ; 1+3 ; 1+3 ; 1+3 ; 1+3
you would only have this if you were to add a 3 pound plastic box to each individual package
Answer:
B. 75.36 cubic cm
Step-by-step explanation:
We will use the formula V=π times r² times h
so, V= 3.14 times 2² times 6
so, V= 3.14 times 4 times 6
= 3.14 times 24
=75.36 cubic cm
<h2><em>
Please mark me as brainliest</em></h2>
Step-by-step explanation:
In my opinion the reason 4 is incorrect
