Answer is: 15675 J.
m (H₂O) = 75g - mass.
ΔT (H₂O)<span> = 75</span>°C - 25°C = 50°C -<span> change in temperature.</span>
C (H₂O) = 4,18 J/g·°C - <span>specific heat of water.
</span>Q = m·C·<span>ΔT.
Q- heat (in Joules-J).
</span>Q = 75g · 50°C · 4,18 J/g·°C = 15675J = 15,675 kJ.
Heat transfer<span> is a discipline that study</span><span> exchange, generation, use and conversion of </span>thermal energy<span> (</span>heat<span>) between physical systems.</span>
This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.
Formula
V / T = V1 / T1
Givens
- V = 56.05 mL
- T = 315.1 degrees Kelvin
- V1 = x
- T1 = 380.5 degrees Kelvin
Solution
56.05/315.1 = x/380.5 Simplify the left.
0.1779 = x / 380.5 Multiply both sides by 380.5
0.1779 * 380.5 = 380.5x/380.5
67.68 mL = x This is your answer
Answer:
There is a lot of empty space between them.
Explanation:
The kinetic molecular theory postulates that a substance is made up of tiny particles called molecules. The molecules of a gas are in constant random motion and collide elastically with each other. They also collide with the walls of the container.
The magnitude of intermolecular forces of attraction between gas molecules is very small. Hence gas molecules are largely apart with a lot of empty space between gas molecules.
Answer:
Zn2+ is colourless
Explanation:
We know that transition metal salts are usually coloured due to the possibility of d-d transition.
This d-d transition can only occur when there are vacant d-orbitals. The electronic configuration [Ar] 4s23d8 suggests the presence of vacant d-orbitals and the possibility of the compounds of Zn2+ being coloured.
However, the absence of colours in Zn2+ compounds shows that there is no d-d transition(electronic) spectra observed for Zn2+ because the d orbitals are completely filled. This means that the correct electronic configuration of the ion is [Ar] 3d10.
