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alexandr1967 [171]
3 years ago
13

Based on the kinetic molecular theory, which of the following statements is correct about the particles in a sample of gas at a

constant temperature and
volume?
They have negligible kinetic energy
They attract each other with strong forces.
There is a lot of empty space between them.
Their net kinetic energy decreases due to collisions.
Chemistry
1 answer:
fgiga [73]3 years ago
8 0

Answer:

There is a lot of empty space between them.

Explanation:

The kinetic molecular theory postulates that a substance is made up of tiny particles called molecules. The molecules of a gas are in constant random motion and collide elastically with each other. They also collide with the walls of the container.

The magnitude of intermolecular forces of attraction between gas molecules is very small. Hence gas molecules are largely apart with a lot of empty space between gas molecules.

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Aqueous acetic acid is neutralized by aqueous barium hydroxide. express your answer as a balanced molecular equation. identify a
Studentka2010 [4]

The balanced molecular equation for the given reaction is:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<h3>FURTHER EXPLANATION</h3>

To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<u>Reactants </u>                  →                 <u>Products</u>

C:  (2 x 2) =4                                  C: (2 x 2) = 4

H: (2 x 4) + (1 x 2) =10                    H: (3 x 2) + (2 X 2) = 10

O: (2 x 2) + (1 x 2) = 6                    O: (2 x 2) + (2 x 1) = 6

Ba: 1                                               Ba: 1

Since the number of atoms of each element are similar in the reactants and products, the equation is balanced.

To determine the state of the substances, consider their solubility.

The reactants are both aqueous (aq) as indicated in the problem.

The first product, Ba(CH_3COO)_2 is aqueous (aq) because based on the solubility rule, it will dissolve in water. Acetates are generally soluble.

The other product is water which will be liquid (l) since it is the solvent used to dissolve the substances.

<h3>LEARN MORE</h3>
  • Solubility Rules brainly.com/question/12984314
  • Net Ionic Equation brainly.com/question/12980075

Keywords: acid-base, neutralization, balancing equations, molecular equation

7 0
3 years ago
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A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8
aivan3 [116]

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = n_1=9.79 mol

Initial volume of freon gas in ballon = V_1=?

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol

Final volume of freon gas in ballon = V_2=21.8 L

Using Avogadro's law:

\frac{V_1}{n_1}=\frac{V_2}{n_2} ( at constant pressure and temperature)

V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L

16.06 L was the initial volume of the balloon.

4 0
3 years ago
Use the Nernst equation to calculate the corresponding voltage if the
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8 0
3 years ago
Calculate the unit cell edge length for an 78 wt% Ag- 22 wt% Pd alloy. All of the palladium is in solid solution, and the crysta
BaLLatris [955]

Answer:

The unit cell edge length for the alloy is 0.405 nm

Explanation:

Given;

concentration of Ag, C_{Ag} = 78 wt%

concentration of Pd, C_P_d = 22 wt%

density of Ag = 10.49 g/cm³

density of Pd = 12.02 g/cm³

atomic weight of Ag, A_A_g = 107.87 g/mol

atomic weight of iron, A_P_d = 106.4 g/mol

Step 1: determine the average density of the alloy

\rho _{Avg.} = \frac{100}{\frac{C_A_g}{\rho _A_g} + \frac{C__{Pd}}{\rho _{Pd}} }

\rho _{Avg.} = \frac{100}{\frac{78}{10.49} + \frac{22}{12.02} } = 10.79 \ g/cm^3

Step 2: determine the average atomic weight of the alloy

A _{Avg.} = \frac{100}{\frac{C_v}{A _A_g} + \frac{C__{Pd}}{A _{Pd}} }

A _{Avg.} = \frac{100}{\frac{78}{107.87} + \frac{22}{106.4} } = 107.54 \ g/mole

Step 3: determine unit cell volume

V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}

for a FCC crystal structure, there are 4 atoms per unit cell; n = 4

V_c=\frac{4*107.54}{ 10.79*6.022*10^{23}} = 6.620*10^{-23} \ cm^3/cell

Step 4: determine the unit cell edge length

Vc = a³

a = V_c{^\frac{1}{3} }\\\\a = (6.620*10^{-23}}){^\frac{1}{3}}\\\\a = 4.05 *10^{-8} \ cm= 0.405 nm

Therefore, the unit cell edge length for the alloy is 0.405 nm

7 0
3 years ago
What is the definition of sound energy
oksian1 [2.3K]

Answer:

Sound energy is the form of energy generated when an object vibrates. Once produced through vibrations, sound energy is transferred in waves through mediums such as air and water before it reaches your ears.

4 0
4 years ago
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