<h2>file:///E:/Kinematics%20Review%208080.pdf</h2><h2></h2><h2>here is your answer</h2>
Answer:
y = 2x + 8
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
6x - 3y = 15 ( subtract 6x from both sides )
- 3y = - 6x + 15 ( divide all terms by - 3 )
y = 2x - 5 ← in slope- intercept form
with slope m = 2
Parallel lines have equal slopes, thus
y = 2x + c ← is the partial equation
To find c substitute (- 2, 4) into the partial equation
4 = - 4 + c ⇒ c = 4 + 4 = 8
y = 2x + 8 ← equation of parallel line
f(x) = −2x + 12, find f(x) when x = −3.
replace x = -3 then
f(-3) = (-2)(-3) + 12
= 6 + 12
=18
Answer is C) f(−3) = 18
f(p)=7/11p-10 Find f(77)
f(77) = 7/11 (77) - 10 (cancel out 77 and 11)
= 7 * 7 - 10
= 49 -10
=39
Answer is D) f(77) = 39
Answer:
z= 0.278
Step-by-step explanation:
Given data
n1= 60 ; n2 = 100
mean 1= x1`= 10.4; mean 2= x2`= 9.7
standard deviation 1= s1= 2.7 pounds ; standard deviation 2= s2 = 1.9 lb
We formulate our null and alternate hypothesis as
H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)
We set level of significance α= 0.05
the test statistic to be used under H0 is
z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂
the critical region is z > ± 1.96
Computations
z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100
z= 10.4- 9.7/ √ 7.29/60 + 3.61/100
z= 0.7/√ 0.1215+ 0.0361
z=0.7 /√0.1576
z= 0.7 (0.396988)
z= 0.2778= 0.278
Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0 at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.
