Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
(6,60),(12,30),(18,20),(24,15)
out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
(6,60) or (12,30)
Answer:
(_1,_7),(_2,_6),(_3,_5),(_4,_4)(_5,_3)
There's only one solution...the one you get when you divide both sides by 22 to solve for x. 902/22 = 41. That exponent on the x, the one you don't see, is a "1" which tells us that there is only 1 solution to this problem. If your x is squared, then you have 2 solutions; if it's cubed, you have 3, etc.
