Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
take away the 15 because you can't multiply a diagonal so 12x18=216 reduce it by the 15 would be the first one sir
Step-by-step explanation:
Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Answer:
1368 dollars.
Step-by-step explanation:
given that Jack s purchasing a stock that pays an annual dividend of $3.42 per share
No of shares Jack purchased = 400
Price per share = 53.18$
Amount invested by Jack in shares = 
dollars
Annual dividend = 3.42 per share
Total dividend = 
Annual income from dividends = 1368 $
Answer:
Multiply 1240 by 1.15 to get 1426 students enrolled this year.
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