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3 years ago

How do I find the length of SW?

Mathematics

1 answer:

baherus [9]3 years ago

5 0

If we assume that ST = 2x + 2, and that TW = 4x - 4, then we can just add the two segments together, as shown below (IF you're asking for the length, that is).

(2x + 2) + (4x - 4)
2x + 2 + 4x - 4
Group together like terms.
(2x + 4x) and (2 - 4)
6x (+) - 2
Answer: 6x - 2

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Please help ( if you can then please help with <br> both questions )

tatuchka [14]

Answer:

For number 1, -1.125 and -9/8. For number 2, -46.

Step-by-step explanation:

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3 years ago

there are 360 students in a school 162 of them are girls find the percent of girls find the percent of boys

Ronch [10]

Answer:

Total number of students = 360

Total number of girls = 120

Total number of boys = x / ?

120/240= 1/2

50%

Step-by-step explanation: To find out the percent of the boys you first

subtract the whole amount of students which is 360 students in total to the number of girls (120) resulting 240. 240 in ratio is 1/2. 1/2 is 50%.

(Not sure, if this helps or not. I try my best to answer questions to make the asker to understand! Sorry, I tried. :c)

7 0

3 years ago

Add and/or Subtract the following, Simplify Completely

Margaret [11]

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3 0

3 years ago

Isabel is using the TVM Solver on her graphing calculator as shown below to determine how much she has to invest now in a saving

Finger [1]

Answer:

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Step-by-step explanation:

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3 years ago

Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each

emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

$A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2$

Jake wants to increase the area by 50%, so the new area would be:

$A'=168(1.5) \\ \\ A'=252ft^2$

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

$(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives$

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

6 0

3 years ago