Ask question

Ask question

All categories

2 years ago

12

How do I find the length of SW?

1 answer:

baherus [9]2 years ago

5 0

If we assume that ST = 2x + 2, and that TW = 4x - 4, then we can just add the two segments together, as shown below (IF you're asking for the length, that is).

(2x + 2) + (4x - 4)
2x + 2 + 4x - 4
Group together like terms.
(2x + 4x) and (2 - 4)
6x (+) - 2
Answer: 6x - 2

You might be interested in

Y -2x is less than or equal to -3

erica [24]

Answer:

EQUAL TO -3

Step-by-step explanation:

7 0

3 years ago

What is 2+2.8/2.45*5.654=

alekssr [168]

8.4617....

Hope this helped you :)

6 0

2 years ago

Read 2 more answers

What is the slope of the graph of x - 2y = 8?<br> A. 0<br> B. 1/2 <br> C. 2<br> D. -1/2

BaLLatris [955]

Answer:

1/2

Step-by-step explanation:

-2y= 8-X

y= -4+X/2

y= X/2-4

recall that: y= mx+c

in the equation y= x/2+C

m=1/2

where m is your slope

7 0

2 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago

Factorization of 4x+7-x

klemol [59]

Answer:

3x+7

Step-by-step explanation:

4x+7-x=4x-x+7=3x+7

8 0

3 years ago