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VARVARA [1.3K]
3 years ago
15

How long does a person going 10 mph (16 kph ) to go .6 miles

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

the answer will be 5

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You spin the spinner shown below once. Each sector shown has an equal area.
a_sh-v [17]

Answer:  P(not shaded sector) = 0.50

Step-by-step explanation:

Since we have given that

Number of shaded parts = 6

Number of unshaded parts = 6

Total parts = 6+6 = 12

So, Probability of getting not shaded sector is given by

\dfrac{6}{12}\\\\=\dfrac{1}{2}\\\\=0.50

Hence, P(not shaded sector) = 0.50

8 0
3 years ago
DBZ<br> 1.<br> 2.<br> 3.<br> $90<br> 9000!!!!
Anna007 [38]

Answer:

dragon ball z sha la a sha la

Step-by-step explanation:

6 0
3 years ago
The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
aniked [119]

Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
3 years ago
What is 11- 9 1/4 simplfy
bija089 [108]

1 and 3/4 is the answer!

Hope this helps! May I have brainliest? :D

8 0
3 years ago
Jeremy buy a new computer with 14 optional features some of the features cost $28.50 and some cost $110.99 he if he spent a tota
makkiz [27]

28.50x + 110.99(14-x)=811.45

distribute

28.50 x + 1553.86-110.99x =811.45

combine like terms

-82.49x+1553.86=811.45

subtract 1553.86 from each side

-82.49x =-742.41

divide by -82.49

x=9

He bought 9 of the 28.50 features and 5 of the 110.99 features

4 0
3 years ago
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