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3 years ago

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Paul's dog has 6 puppies. Three of them are a mixture of black and white, two are all black, and one is all white. Express as a

fraction the numbers that are... (hint: do not reduce the fractions) Black and white: _/_ all back: _/_ all white: _/_

1 answer:

Ludmilka [50]3 years ago

3 0

Answer:

Black and white = 3/6

All Black = 2/6

All White = 1/6

Step-by-step explanation:

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Use the drop-down menus to complete the statements to match the information shown by the graph. A graph has weight (pounds) on t

NISA [10]

Answer:

Your drop down menus have the following choices:

First box: faster than, slower than, at the same rate as.

Second box: greatest x-value, line, y-intercept, slope.

Third box: greater than, less than, equal to.

Fourth box: greatest x-value, x-intercept, y-intercept, slope, origin.

Fifth box: minutes per gallon, gallons per minute.

Pool A is filling up slower than Pool B because the slope of the graph of Pool A is less than that of the graph for Pool B.

The slope of the graph tells you the unit rate in gallons per minute.

Step-by-step explanation:

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3 years ago

Write an algebraic expression that represents<br> the following phrase:<br> The product of 8 and 12

Ainat [17]

Answer:

$8*12$

Step-by-step explanation:

First, the problem asks for an expression; this means that there should be no equal sign. Also, the keyword "product" means that both the terms must be multiplied. So, $8*12$ is the final expression; this equals 96.

6 0

3 years ago

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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3 years ago

All vectors are in Rn. Check the true statements below:

Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

$Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y$

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that $||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}$ . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then $||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||$ .

C) Consider $S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2$ . This set is orthogonal because $(0,2)\cdot(2,0)=0(2)+2(0)=0$ , but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in $\mathbb{R}^n$ . Then the columns of A form an orthonormal set. We have that $A^{-1}=A^t$ . To see this, note than the component $b_{ij}$ of the product $A^t A$ is the dot product of the i-th row of $A^t$ and the jth row of $A$ . But the i-th row of $A^t$ is equal to the i-th column of $A$ . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then $A^t A=I$

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set $\{u_1,u_2\cdots u_p\}$ and suppose that there are coefficients a_i such that $a_1u_1+a_2u_2\cdots a_nu_n=0$ . For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then $a_i||u_i||=0$ then $a_i=0$ .

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3 years ago

A minor league baseball team plays 122 games in a season. If the team won 14 more than three times as many games as they lost,

Leviafan [203]

W + L = 122
W = 3L + 14

3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games

W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games

8 0

3 years ago