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nlexa [21]
3 years ago
14

Paul's dog has 6 puppies. Three of them are a mixture of black and white, two are all black, and one is all white. Express as a

fraction the numbers that are... (hint: do not reduce the fractions) Black and white: _/_ all back: _/_ all white: _/_
Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

Black and white = 3/6

All Black = 2/6

All White = 1/6

Step-by-step explanation:

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Label the percent bar below with the appropriate estimations.
Lapatulllka [165]

100÷4=25

25×4=100

so the answers for the a,b,and c is 25%

3 0
3 years ago
Alex rolls a 6-sided dice ten times.
Angelina_Jolie [31]

Answer:

Hello Love! The median is simply just the number in the middle so sense we have 2 numbers in the middle our median will be 3 and 6

The mean is when you add up the numebers then divide by how many numbers there are so...

3 + 2 + 4 + 6 + 3 + 6 + 1 + 2 + 5 + 4 = 36 so 36 divided by 10 is 3.6

The range is simply just the biggest number in the sequence subtracted by the smallest number so... 6 - 1 = 5 so 5 would be our range!

Hope this helps you.

3 0
3 years ago
2. Solve x - 19 <81. Then graph the solution.
mr_godi [17]

Answer:

x<100

Step-by-step explanation:

The given equation is :

x-19<81

Adding 19 to both sides of the equation.

x-19+19<81+19

x<100

It means the solution of the given equation is less than 100. Hence, the attached figure shows the graph for the given equation.

4 0
3 years ago
Help plzzzz I need the correct answers ASAP and that's my last marking period 4 and I'm in grade 12th
Lemur [1.5K]

Answer:

try c

Step-by-step explanation:

8 0
3 years ago
A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
4 years ago
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