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Anastaziya [24]
3 years ago
14

The cafeteria has 6 round tables and 23 rectangular tables. If each round table has 7 chairs and each rectangular table has 18 c

hairs, how many chairs are there in the cafeteria?
Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer: 456 chairs

Step-by-step explanation:

If there are 6 round tables with 7 chairs each you would multiply 7, 6 times (7 x 6) = 42

If there are 23 rectangular tables with 18 chairs each you would multiply 18, 23 times. ( 18 x 23) = 414

Then you add up all the chairs, 456 chairs total.

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a mixture of 40 liters of paint is 25% red tint, 30% yellow tint and 45% water. 6 liters of yellow tint are added to the origina
irakobra [83]
40 liters.....30% is yellow tint
0.30(40) = 12 liters are yellow

if u add 6 liters....(12 + 6) = 18 liters are now yellow...and since u added 6 liters, ur total mixture is now 46 liters.
18/46 = 0.39 = 39% <===
5 0
3 years ago
Christopher bought 4 pens that cost the same amount of money and a marker that cost $3. He spent a total of $11. Which statement
Nikolay [14]
The pens cost $2 each.
2*4+3=11
8 0
3 years ago
A tree casts a shadow 21m long. The angle of elevation of the sun is 55 degrees. What is the height of the tree?
Orlov [11]

Answer:

The height of the tree is about 30 feet.

Step-by-step explanation:

tan(55) = h/21

*21          *21

21*tan(55)=h

29.99=h

h=29.99=30 feet

4 0
3 years ago
Write as a numerical expression: “ Six less than twice a number is four “
VladimirAG [237]

Answer:

2x - 6 = 4

Step-by-step explanation:

Firstly, let's assume the number is x

Then, twice the number is 2 times x = 2x

6 less than twice the number is four

2x - 6 = 4

2x - 6 + 6 = 4 + 6

2x = 10

2x/2 = 10/2

x = 5

6 0
3 years ago
In one jar, I have two balls labelled 1 and 2 respectively. In a second jar, I have three balls labelled 0, 1 and 2 respectively
PolarNik [594]

Step-by-step explanation:

this is a kind of trick question, actually.

with whatever we draw, we produce X values as power of 3.

to be precise, we can have only

3⁰ = 1

3¹ = 3

3² = 9

3⁴ = 81

due to the possible combinations of drawn numbers (e.g. 3 cannot be created by a multiplication of 0s, 1s and 2s).

so, mostly, these results cannot be exact factors of 1024.

1024 cannot be divided by 3, nor by 9 nor by 81.

but 1024 is a multiple of 1 (as is every number).

so, we are looking at the probability to get 0 as multiplication result of the numbers on the 2 drawn balls.

the only possibilities are

1 and 0

2 and 0

out of in total 6 (2×3) different outcomes

1 and 0

1 and 1

1 and 2

2 and 0

2 and 1

2 and 2

the probability of this "0" event is again

number of desired outcomes / number of possible outcomes = 2/6 = 1/3

6 0
2 years ago
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