3a- 2b + 8b - 2 + 6a + 3c
3a + 6a -2b +8b + 3c - 2
9a + 6b + 3c - 2
For this case what you should do is use the following trigonometric relationship:
tan (x) = C.O / C.A
Where
x: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting the values we have:
tan (60) = long / short
tan (60) = long / 2
long = 2 * tan (60)
long = 3.46
Answer:
long = 3.46
It's C the missing side is 9 units long so since cosine is adjacent divided by hypotenuse it would be 9/41
