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Soloha48 [4]
3 years ago
6

Which of the following likely comes last in developing a presentation outline

Computers and Technology
2 answers:
kari74 [83]3 years ago
8 0
So in developing a presentation outline, the first thing that we are going to do is to introduce what it is all about. This means that the main points come first. After the main points, follow the sub points. The sub points serve as the explanation of the main points. After the sub points are the illustrations and examples. These are already the specifics which support the sub points and the main points. Therefore, the answer is A.
Andreyy893 years ago
5 0

Answer:

The answer is illustrations/examples

Explanation:

Think of carving a sculpture. When carving you will start by chipping away at big chunks of clay, this is your main points. Then after the big chunks of clay are gone you will start to create the shape of your sculpture. You will chisel away at your clay with a more precise tool which are your sub-points. After the figure of your sculpture is defined you will start to create more details, this is your illustrations/examples.

Btw I've never sculpted anything but I generally know how to I guess. Also if that explanation wasn't enough for you, I just answer that question on a quiz and it said I was right so...

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A. review or print them later
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Read 2 more answers
ISO 400 is twice as sensitive and ISO 100 true or false
beks73 [17]

Answer:

Quite simply, when you double your ISO speed, you are doubling the brightness of the photo. So, a photo at ISO 400 will be twice brighter than ISO 200, which will be twice brighter than ISO 100.

Explanation:

ISO most often starts at the value of ISO 100. This is the lowest, darkest setting, also called the base ISO. The next full stop, ISO 200, is twice as bright, and ISO 400 is twice as bright than that. Thus, there are two stops between ISO 100 and 400, four stops between 100 and 1600, and so on.

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3 years ago
Have you searched Buzz Ch.at on playstore​
deff fn [24]

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

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3 0
3 years ago
Match the different sources of payments to their descriptions. an electronic device that aids consumers to make online payments
LekaFEV [45]

<u>Automatic Draft-</u> A convenient payment method where funds are automatically debited from your account.

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For anyone still looking, hope this helps.

6 0
3 years ago
Write a program that asks the user how many numbers will be entered and then has the user enter those numbers. When this is done
KATRIN_1 [288]

Answer:

<em>The program written in Python 3 is as follows;</em>

<em>The program does not make use of comments; however, see explanation section for detailed line by line explanation of the program</em>

num = int(input("Number of Inputs: "))

mylist = []

userinput = int(input("Enter a digit: "))

i = 1

while i < num:

     mylist.append(userinput)

     userinput = int(input("Enter a digit: "))

     i += 1

   

try:

     first7 = mylist.index(7)+1

     print('The first position of 7 is ',first7)

     last7 = num - 1 - mylist[::-1].index(7)

     print('The last position of 7 is ',last7)

except:

     print('7 is not on the list')

Explanation:

This line prompts user for the number of inputs

num = int(input("Number of Inputs: "))

This line declares an empty list

mylist = []

This line inputs the first number into the empty list

userinput = int(input("Enter a digit: "))

The italicized lines represent an iteration that allows user to input the numbers into the empty list.

<em>i = 1</em>

<em>while i < num:</em>

<em>      mylist.append(userinput)</em>

<em>      userinput = int(input("Enter a digit: "))</em>

<em>      i += 1</em>

The try-except is used to check the presence of 7 in the list

try:

This checks the first occurrence of 7

     first7 = mylist.index(7)+1

This prints the first occurrence of 7

     print('The first position of 7 is ',first7)

This checks the last occurrence of 7

     last7 = num - 1 - mylist[::-1].index(7)

This prints the last occurrence of 7

     print('The last position of 7 is ',last7)

The following is executed if there's no occurrence of 7

except:

     print('7 is not on the list')

See Attachments for sample runs

7 0
3 years ago
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